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Jamia Millia Islamia Previous Year Questions (PYQs)

Jamia Millia Islamia 2022 PYQ


Jamia Millia Islamia PYQ 2022
Which out of these statements is NOT true:





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2023 PYQ

Solution

Solution: All three statements (A), (B), and (C) are correct according to C language behavior. Hence, there is **no incorrect statement**.

Jamia Millia Islamia PYQ 2022
The instructions for starting the computer are housed in ____.





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

 Boot/firmware (BIOS/UEFI) is stored in non-volatile ROM.

Jamia Millia Islamia PYQ 2022
____ is the process of dividing the disk into tracks and sectors.





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

Formatting lays out tracks/sectors (low-level) and file-system structures.


Jamia Millia Islamia PYQ 2022
In MICR, C stands for ______.





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

Magnetic Ink Character Recognition.


Jamia Millia Islamia PYQ 2022
The terms Goodput, Throughput, Maximum throughput are most closely associated with which among the following?





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

 They are network/data-transfer rate measures.

Jamia Millia Islamia PYQ 2022
What will be the output of the statement printf(3+"goodbye");





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

"goodbye" is a char array; 3 + "goodbye" points to the 4th char → "dbye".

Jamia Millia Islamia PYQ 2022
What will be the output of the statements? 
int i = 1, j;
j = i-- - -2;
printf("%d", j);






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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

i-- uses the old value 1, then i becomes 0. Expression is 1 - (-2) = 3.

Jamia Millia Islamia PYQ 2022
What will be output of following statements?
int i = 1, j;
j = --i - 2;
printf("%d", j);






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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

i = 1 → --i = 0 → j = 0 - 2 = -2

Jamia Millia Islamia PYQ 2022
What is the output of following C Program?
#include <stdio.h>
int main()
{
    char grade[] = {'A','B','C'};
    printf("GRADE=%c, ", *grade);
    printf("GRADE=%d", grade);
    return 0;
}






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Solution

*grade = 'A', grade = base address of array Output: GRADE=A, GRADE=some address of array

Jamia Millia Islamia PYQ 2022
Which one is not a reserve keyword in C Language?





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

main (function name, not a keyword).

Jamia Millia Islamia PYQ 2022
What is the output of following C program:

int main(){
  int a[3]={10,12,14};
  a[1]=20; int i=0;
  while(i<3){ printf("%d ", a[i]); i++; }
  return 0;
}






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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

main (function name, not a keyword).

Jamia Millia Islamia PYQ 2022
The number of groups that can be made from 5 different green balls, 4 different blue balls and 3 different red balls, if at least 1 green and 1 blue ball is to be included 





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Solution


Jamia Millia Islamia PYQ 2022
In a unique hockey series between India & Pakistan, they decide to play on till a team wins 5 matches.
The number of ways in which the series can be won if no match ends in a draw is:





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

To win, one team must reach 5 wins before the other. Total possible ways = $2 \times \sum_{k=0}^{4} \binom{4+k}{k} = 2(1 + 5 + 15 + 35 + 70) = 252$

Jamia Millia Islamia PYQ 2022
20 persons are sitting in a particular arrangement around a circular table.
3 persons are to be selected for leaders.
The number of ways of selection of 3 persons such that no 2 were sitting adjacent to each other is:





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

For circular arrangement, required formula: $\text{Ways} = \dfrac{n}{n - r} \binom{n - r}{r}$ Substitute $n=20, r=3$ $\Rightarrow \text{Ways} = \dfrac{20}{17} \binom{17}{3} = 20 \times 68 / 17 = 800$

Jamia Millia Islamia PYQ 2022
If A and B are two independent events in a sample space, then $P(\overline{A}/\overline{B})$ equals:





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

For independent events: $P(\overline{A}/\overline{B}) = P(\overline{A}) = 1 - P(A)$

Jamia Millia Islamia PYQ 2022
100 identical coins, each with probability $p$ of showing heads, are tossed. If $0 < p < 1$ and the probability of showing heads on 50 coins is equal to that of 51 coins, then the value of $p$ is:





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Solution

$\binom{100}{50}p^{50}(1-p)^{50} = \binom{100}{51}p^{51}(1-p)^{49}$ $\Rightarrow \dfrac{\binom{100}{50}}{\binom{100}{51}} \cdot \dfrac{1-p}{p} = 1$ $\dfrac{\binom{100}{50}}{\binom{100}{51}} = \dfrac{51}{50}$ $\Rightarrow \dfrac{1-p}{p} = \dfrac{50}{51}$ $\Rightarrow p = \dfrac{51}{101}$

Jamia Millia Islamia PYQ 2022
At any time, the total number of people on the earth who have shaken hands an odd number of times is:





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Solution

By the Handshake Lemma, in any graph, the number of vertices with odd degree is always even.

Jamia Millia Islamia PYQ 2022
Let two fair six-faced dice $A$ and $B$ be thrown simultaneously. Let $E_1$ be the event that die $A$ shows 4, $E_2$ the event that die $B$ shows 2, and $E_3$ the event that the sum of the two numbers on the dice is odd. Which statement is false?





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Solution

$P(E_1) = P(E_2) = \dfrac{1}{6}, \quad P(E_3) = \dfrac{1}{2}$ $P(E_1 \cap E_2 \cap E_3) = 0$ (since $4 + 2 = 6$, even) $P(E_1)P(E_2)P(E_3) = \dfrac{1}{72}$ So they are pairwise independent, but not mutually independent.

Jamia Millia Islamia PYQ 2022
The sum of 3 numbers in A.P. is $-3$ and their product is $8$. Then the sum of squares of the numbers is:





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Solution

Let the numbers be $a - d,\ a,\ a + d$. $3a = -3 \Rightarrow a = -1$ $(a - d)a(a + d) = 8$ $\Rightarrow -1(1 - d^2) = 8 \Rightarrow d^2 = 9$ Sum of squares $= 3a^2 + 2d^2 = 3(1) + 2(9) = 21$

Jamia Millia Islamia PYQ 2022
If $x,\ 2x + 2,\ 3x + 3$ are in G.P., then the 4th term is:





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Solution

For G.P., $(2x + 2)^2 = x(3x + 3)$ $4x^2 + 8x + 4 = 3x^2 + 3x$ $\Rightarrow x^2 + 5x + 4 = 0$ $\Rightarrow x = -1$ or $x = -4$ For non-trivial case, $x = -4$ Then terms are $-4, -6, -9$ and ratio $r = \dfrac{3}{2}$ 4th term $= -4 \times \left(\dfrac{3}{2}\right)^3 = -13.5$

Jamia Millia Islamia PYQ 2022
In a sequence of $21$ terms, the first $11$ terms are in A.P. with common difference $2$ and the last $11$ terms are in G.P. with common ratio $2$. If the middle term of A.P. is equal to the middle term of G.P., then the middle term of the entire sequence is





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Solution

Let $t_1$ be the first term. For the A.P.: $t_6=t_1+10$, $t_{11}=t_1+20$. For the G.P. (terms $11$ to $21$ with ratio $2$): $t_{16}=t_{11}\cdot 2^5=32t_{11}$. Given $t_6=t_{16}$: $t_1+10=32(t_1+20)\Rightarrow 31t_1=-630\Rightarrow t_1=-\dfrac{630}{31}$. Middle term of entire sequence is $t_{11}=t_1+20=-\dfrac{630}{31}+20=-\dfrac{10}{31}$.

Jamia Millia Islamia PYQ 2022
If $1,\ \log_{9}!\left(3^{,1-x}+2\right)$ and $\log_{3}!\left(4\cdot 3^{x}-1\right)$ are in A.P., then $x$ equals





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Solution

A.P. $\Rightarrow 2\cdot\log_{9}(3^{1-x}+2)=1+\log_{3}(4\cdot 3^x-1)$. Since $\log_{9}y=\dfrac12\log_{3}y$, we get $\log_{3}(3^{1-x}+2)=1+\log_{3}(4\cdot 3^x-1)=\log_{3}!\big(3(4\cdot 3^x-1)\big)$. Hence $3^{1-x}+2=12\cdot 3^{x}-3$. Put $t=3^x$: $\dfrac{3}{t}+2=12t-3$. $\Rightarrow 12t^2-5t-3=0 \Rightarrow t=\dfrac{3}{4}$ (positive root). So $3^x=\dfrac{3}{4}\Rightarrow x=\log_{3}!\left(\dfrac{3}{4}\right)=1-\log_{3}4$.

Jamia Millia Islamia PYQ 2022
Ram secures $100$ marks in maths, then he will get a smartphone.” The converse is:





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Solution

Converse of “$P\Rightarrow Q$” is “$Q\Rightarrow P$”. $\boxed{\text{If Ram will get a smartphone, then he secures 100 marks in maths.}}$

Jamia Millia Islamia PYQ 2022
Negation of $,q \vee \sim (p \wedge r),$ is





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Solution

$\neg\big(q \vee \neg(p\wedge r)\big)=\neg q \wedge \neg\neg(p\wedge r)=\neg q \wedge (p\wedge r)$. $\boxed{,\sim q \wedge (p \wedge r),}$

Jamia Millia Islamia PYQ 2022
The median of a set of $9$ distinctive observations is $20.5$. If each of the largest $4$ observations of the set is increased by $2$, then the median of the new set





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Solution

For $9$ observations, median is the $5^{\text{th}}$ term. Increasing the top $4$ (positions $6$–$9$) does not change the $5^{\text{th}}$ value.

Jamia Millia Islamia PYQ 2022
The variance of first $50$ even natural numbers is





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Solution

Numbers are $2,4,\dots,100=2\cdot{1,\dots,50}$. $\operatorname{Var}(1,\dots,50)=\dfrac{50^2-1}{12}=\dfrac{2499}{12}=\dfrac{833}{4}$. Scaling by $2$: $\operatorname{Var}=4\cdot\dfrac{833}{4}=833$.

Jamia Millia Islamia PYQ 2022
$(p\wedge \neg q)\wedge(\neg p\wedge q)$ is





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

Expression forces $p\wedge\neg p$ and $q\wedge\neg q$ simultaneously → impossible. $\boxed{\text{Contradiction}}$

Jamia Millia Islamia PYQ 2022
Marks obtained by $4$ students are: $25,35,45,55$. The average deviation from the mean is





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Solution

$= \dfrac{25+35+45+55}{4}=40$. Absolute deviations: $|25-40|,|35-40|,|45-40|,|55-40|=15,5,5,15$. Average deviation $=\dfrac{15+5+5+15}{4}=10$.

Jamia Millia Islamia PYQ 2022
The numbers $3, 5, 7, 4$ have frequencies $x, x+4, x-3, x+8$. If their arithmetic mean is $4$, then the value of $x$ is:





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Solution

$\text{Mean} = \dfrac{3x + 5(x+4) + 7(x-3) + 4(x+8)}{x + (x+4) + (x-3) + (x+8)} = 4$ $\Rightarrow \dfrac{19x + 33}{4x + 9} = 4$ $\Rightarrow 19x + 33 = 16x + 36$ $\Rightarrow 3x = 3$ $\Rightarrow x = 1$

Jamia Millia Islamia PYQ 2022
For two datasets each of size $5$, variances are $4$ and $5$ and means are $2$ and $4$ respectively. The variance of the combined dataset is:





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Solution

Let $n_1 = n_2 = 5, ; \sigma_1^2 = 4, ; \sigma_2^2 = 5, ; \bar{x}_1 = 2, ; \bar{x}_2 = 4$ Then $\sigma^2 = \dfrac{n_1\sigma_1^2 + n_2\sigma_2^2}{n_1+n_2} + \dfrac{n_1(\bar{x}_1 - \bar{x})^2 + n_2(\bar{x}_2 - \bar{x})^2}{n_1+n_2}$ where $\bar{x} = \dfrac{n_1\bar{x}_1 + n_2\bar{x}_2}{n_1+n_2} = 3$ $\Rightarrow \sigma^2 = \dfrac{5(4) + 5(5)}{10} + \dfrac{5(1)^2 + 5(1)^2}{10}$ $= 4.5 + 1 = 5.5 = \boxed{11/2}$

Jamia Millia Islamia PYQ 2022
If $ \begin{vmatrix} x & 3 & 6 \\ 3 & 6 & x \\ 6 & x & 3 \end{vmatrix} = \begin{vmatrix} 2 & x & 7 \\ x & 7 & 2 \\ 7 & 2 & x \end{vmatrix} = \begin{vmatrix} 4 & 5 & x \\ 5 & x & 4 \\ x & 4 & 5 \end{vmatrix} = 0 $, then $x$ is equal to:





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Solution

For determinant $\begin{vmatrix}x & 3 & 6 \ 3 & 6 & x \ 6 & x & 3\end{vmatrix} = 0$ Expanding, we get: $x(6×3 - x×x) - 3(3×3 - x×6) + 6(3×x - 6×6) = 0$ $\Rightarrow x(18 - x^2) - 3(9 - 6x) + 6(3x - 36) = 0$ $\Rightarrow -x^3 + 18x - 27 + 18x + 18x - 216 = 0$ $\Rightarrow -x^3 + 54x - 243 = 0$ $\Rightarrow x^3 - 54x + 243 = 0$ By trial, $x=9$ satisfies it. Hence $\boxed{x = 9}$

Jamia Millia Islamia PYQ 2022
If $ \begin{vmatrix} a & p & x \\ b & q & y \\ c & r & z \end{vmatrix} = 16 $, then the value of $ \begin{vmatrix} p+q & a+x & a+p \\ q+y & b+y & b+q \\ x+z & c+z & c+r \end{vmatrix} $ is:





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Solution

By properties of determinants, each column in the second determinant is the **sum of two columns** of the first. So its value remains the same (since addition of columns preserves linearity). Hence $\boxed{16}$.

Jamia Millia Islamia PYQ 2022
If $ \begin{vmatrix} x & 3 & 6 \\ 3 & 6 & x \\ 6 & x & 3 \end{vmatrix} = \begin{vmatrix} 2 & x & 7 \\ x & 7 & 2 \\ 7 & 2 & x \end{vmatrix} = \begin{vmatrix} 4 & 5 & x \\ 5 & x & 4 \\ x & 4 & 5 \end{vmatrix} = 0 $, then $x$ is equal to:





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Solution

Expanding the first determinant, $ x(6\times3 - x\times x) - 3(3\times3 - x\times6) + 6(3\times x - 6\times6) $ $ = x(18 - x^2) - 3(9 - 6x) + 6(3x - 36) $ $ = -x^3 + 54x - 243 = 0 $ $\Rightarrow x^3 - 54x + 243 = 0$ Trial gives $x = 9$. $\boxed{x = 9}$ → (D) None of these.

Jamia Millia Islamia PYQ 2022
Evaluate the following integral: $ \int_{-2}^{2} \frac{3x^3 + 2|x| + 1}{x^2 + |x| + 1}\,dx $





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Solution

Note $f(x) = \dfrac{3x^3 + 2|x| + 1}{x^2 + |x| + 1}$ is **odd + even combination**, so integrate separately. After simplifying using $|x|$ symmetry and limits $[-2,2]$, only even part contributes. Result $= 3\log 7$.

Jamia Millia Islamia PYQ 2022
If $A,B,C$ are angles of a triangle, then the value of $ \begin{vmatrix} \sin 2A & \sin C & \sin B \\ \sin C & \sin 2B & \sin A \\ \sin B & \sin A & \sin 2C \end{vmatrix} $ is:





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Solution

** Since $A+B+C=\pi$, we have $\cos A=-\cos(B+C)=\sin B\sin C-\cos B\cos C$ and similarly for $B,C$. Using $\sin 2A=2\sin A\cos A$ (and cyclic forms), each row becomes a linear combination of the other two rows, so the rows are linearly dependent. Hence the determinant is $0$. $\boxed{0}$

Jamia Millia Islamia PYQ 2022
Evaluate the following integral: $ \int_{-\pi/2}^{\pi/2} \log\!\left(\frac{2-\sin x}{2+\sin x}\right)\,dx $





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Solution

Let $f(x)=\log\!\left(\frac{2-\sin x}{2+\sin x}\right)$. Then $f(-x)=\log\!\left(\frac{2+\sin x}{2-\sin x}\right)=-f(x)$, so $f$ is odd. Integral over $[-\pi/2,\pi/2]$ of an odd function is $0$.

Jamia Millia Islamia PYQ 2022
Solve the differential equation: $x\,\dfrac{dy}{dx}+1=0;\; y(-1)=0$





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Solution

$\dfrac{dy}{dx}=-\dfrac{1}{x}\;\Rightarrow\; y=-\ln|x|+C$. Using $y(-1)=0$ gives $C=0$. Hence $y=-\ln|x|$ (same as $-\log|x|$ up to base).

Jamia Millia Islamia PYQ 2022
If the matrix product $AB=0$, then which is true?





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Solution

In general $AB=0\nRightarrow A=0$ or $B=0$. Example: $A=\begin{pmatrix}1&0\\0&0\end{pmatrix}$,\; $B=\begin{pmatrix}0&0\\1&0\end{pmatrix}$ are non-zero but $AB=\begin{pmatrix}0&0\\0&0\end{pmatrix}$. So $\boxed{\text{(A)}}$

Jamia Millia Islamia PYQ 2022
Which statement is false?





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Solution

Continuity of $f(x)$ at $x=a$ does **not imply** that its inverse $f^{-1}(x)$ is continuous there (the inverse may not even exist). $\boxed{(B)}$

Jamia Millia Islamia PYQ 2022
The function $f$ is defined in $[-5,5]$ as $ f(x)= \begin{cases} x, & \text{if }x\text{ is rational}\\ -x, & \text{if }x\text{ is irrational} \end{cases} $





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Solution

For rationals $f(x)=x$, for irrationals $f(x)=-x$. At $x=0$, both give $0$, so it’s continuous there. At any $x\neq0$, limits from rationals and irrationals differ.

Jamia Millia Islamia PYQ 2022
The relation $R=\{(1,1),(2,2),(3,3),(1,2),(2,3),(1,3)\}$ on $A=\{1,2,3\}$ is:





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Solution

Reflexive — yes (all $(a,a)$ are present). Symmetric — no, since $(1,2)\in R$ but $(2,1)\notin R$. Transitive — yes, because $(1,2)$ and $(2,3)$ imply $(1,3)$ (which exists).

Jamia Millia Islamia PYQ 2022
For real numbers $x,y$, define $x\,R\,y$ iff $x-y+\sqrt{2}$ is irrational. Then the relation $R$ is:





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Solution

For reflexivity: $xRx$ means $x-x+\sqrt{2}=\sqrt{2}$ (irrational) ⇒ true. For symmetry: $xRy⇒x-y+\sqrt{2}$ irrational, but $y-x+\sqrt{2}=-(x-y)+\sqrt{2}$ may be rational. Not always true ⇒ not symmetric. For transitivity: fails similarly.

Jamia Millia Islamia PYQ 2022
If $f(x)=ax^7+bx^3+cx-5$, where $a,b,c$ are real constants, and $f(-7)=7$, then the range of $f(7)+17\cos x$ is:





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Solution

$f(7)=-(f(-7))= -7 + 10 = 27$ (since odd-powered terms change sign). Actually, $f(7)=-f(-7)-10=...$ simplifying gives $f(7)=17$. Then $f(7)+17\cos x = 17 + 17\cos x$. Range = $[17-17,17+17]=[0,34]$.

Jamia Millia Islamia PYQ 2022
If $z$ is any complex number with $|z-3-2i|\le2$, then the minimum of $|\,2z-6+5i\,|$ is:





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Solution

Put $w=z-(3+2i)$ so $|w|\le2$. Then $2z-6+5i=2w+9i$. Set of $2w$ is a disc of radius $4$ centered at $0$, so $2w+9i$ is a disc of radius $4$ centered at $9i$. Minimum modulus $=\big||9|-4\big|=5$.

Jamia Millia Islamia PYQ 2022
The domain of $\sqrt{|x-2|-1}+\sqrt{\,3-|x-2|\,}$ is:





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Solution

$\sqrt{|x-2|-1}$ needs $|x-2|\ge1\Rightarrow x\le1$ or $x\ge3$. $\sqrt{3-|x-2|}$ needs $|x-2|\le3\Rightarrow x\in[-1,5]$. Intersection $\Rightarrow [-1,1]\cup[3,5]$.

Jamia Millia Islamia PYQ 2022
For $z\ne0$, the value of $\arg z+\arg\overline{z}$ is:





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Solution

$\arg(\overline{z})=-\arg(z)$ (principal values). Hence sum $=0$.

Jamia Millia Islamia PYQ 2022
The value(s) of $b$ for which the equations $x^2+bx-1=0$ and $x^2+x+b=0$ have one root in common is/are:





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Solution

Let common root be $r$. Then $r^2+br-1=0$ and $r^2+r+b=0$. Subtract: $r(1-b)+(b+1)=0\Rightarrow r=\dfrac{b+1}{b-1}$ (for $b\ne1$). Substitute in $r^2+br-1=0$: \[ \frac{(b+1)^2}{(b-1)^2}+b\frac{b+1}{b-1}-1=0 \;\Rightarrow\; b^3+3b=0 \;\Rightarrow\; b\,(b^2+3)=0. \] Hence $b=0$ or $b=\pm i\sqrt3$.

Jamia Millia Islamia PYQ 2022
The coefficient of $y$ in the expansion of $\left(y^2+\dfrac{c}{y}\right)^5$ is:





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

General term $T_k=\binom{5}{k}(y^2)^{5-k}\left(\dfrac{c}{y}\right)^k =\binom{5}{k}c^k\,y^{10-3k}$. For power of $y^1$: $10-3k=1\Rightarrow k=3$. Coefficient $=\binom{5}{3}c^3=10c^3$.

Jamia Millia Islamia PYQ 2022
In the expansion of $(1+x)^{50}$, the sum of coefficients of odd powers of $x$ is:





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

Sum of odd coefficients $=\dfrac{(1+1)^{50}-(1-1)^{50}}{2} =\dfrac{2^{50}-0}{2}=2^{49}$.

Jamia Millia Islamia PYQ 2022
If $R$ is the largest equivalence relation on a set $A$ and $S$ is any relation on $A$, then:





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

Largest equivalence on $A$ is $A\times A$ (universal relation), so every relation $S$ on $A$ satisfies $S\subseteq A\times A=R$.

Jamia Millia Islamia PYQ 2022
The number of $4$-digit numbers that can be formed with digits $0,1,2,3,4,5,6,7$ such that each number contains the digit $1$ is:





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

(interpreting “contains 1” as **exactly one** ‘1’, repetitions allowed):** Case-1: ‘1’ in the thousand’s place → remaining $3$ places from $\{0,\dots,7\}\setminus\{1\}$ with repetition: $7^3=343$ ways. Case-2: ‘1’ in any one of the last three places ($3$ choices). Thousand’s place from $\{2,\dots,7\}$ ($6$ ways). Remaining two places from $\{0,\dots,7\}\setminus\{1\}$ with repetition: $7^2=49$ ways. Total $=343+3\cdot6\cdot49=343+882

Jamia Millia Islamia PYQ 2022
Prototype of a function means ____





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

(interpreting “contains 1” as **exactly one** ‘1’, repetitions allowed):** Case-1: ‘1’ in the thousand’s place → remaining $3$ places from $\{0,\dots,7\}\setminus\{1\}$ with repetition: $7^3=343$ ways. Case-2: ‘1’ in any one of the last three places ($3$ choices). Thousand’s place from $\{2,\dots,7\}$ ($6$ ways). Remaining two places from $\{0,\dots,7\}\setminus\{1\}$ with repetition: $7^2=49$ ways. Total $=343+3\cdot6\cdot49=343+882

Jamia Millia Islamia PYQ 2022
Far pointer can access ____





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

(interpreting “contains 1” as **exactly one** ‘1’, repetitions allowed):** Case-1: ‘1’ in the thousand’s place → remaining $3$ places from $\{0,\dots,7\}\setminus\{1\}$ with repetition: $7^3=343$ ways. Case-2: ‘1’ in any one of the last three places ($3$ choices). Thousand’s place from $\{2,\dots,7\}$ ($6$ ways). Remaining two places from $\{0,\dots,7\}\setminus\{1\}$ with repetition: $7^2=49$ ways. Total $=343+3\cdot6\cdot49=343+882

Jamia Millia Islamia PYQ 2022
A pointer that is pointing to NOTHING is called ____  





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Solution

Null pointer

Jamia Millia Islamia PYQ 2022
What is the similarity between a structure, union and enumeration?  





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

 All of them let you define new data types

Jamia Millia Islamia PYQ 2022
 How will you free the allocated memory?  





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

 All of them let you define new data types

Jamia Millia Islamia PYQ 2022
Which of the following describes the characteristics of SRAM?





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

 All of them let you define new data types

Jamia Millia Islamia PYQ 2022
The primary memory (main memory) of a personal computer consists of





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

 Main memory = RAM (ROM is not part of main working memory).

Jamia Millia Islamia PYQ 2022
Which of the following has the fastest speed in the computer memory hierarchy?





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

CPU registers are the fastest.

Jamia Millia Islamia PYQ 2022
In which type of memory, once the program or data is written, it cannot be changed?






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Solution

 PROM (one-time programmable).

Jamia Millia Islamia PYQ 2022
In which type of ROM, data can be erased by ultraviolet light and then reprogrammed by the user or manufacturer?





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

EPROM (UV-erasable, reprogrammable).

Jamia Millia Islamia PYQ 2022
In which numbering system can the binary number 1011011111000101 be easily converted to?





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

Grouping binary in 4 bits maps directly to hex.

Jamia Millia Islamia PYQ 2022
Which bitwise operator is suitable for turning off a particular bit in a number?





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

Use bitwise AND with a mask having 0 at that bit.

Jamia Millia Islamia PYQ 2022
Convert (231)_4 into (____)_3.





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

 (231)_4 = 2·4^2 + 3·4 + 1 = 45_(10).
45 to base 3 → 1·3^3 + 2·3^2 + 0·3 + 0 = 1200_3.

Jamia Millia Islamia PYQ 2022
Convert (1278)_12 into (____)_4.





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

(1278)_12 = 1·12^3 + 2·12^2 + 7·12 + 8 = 2108_(10).
2108 to base 4:
= 2·4^5 + 0·4^4 + 0·4^3 + 3·4^2 + 3·4 + 0 = 200330_4.

Jamia Millia Islamia PYQ 2022
Convert (110100)_2 into (____)_16





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

 110100₂ = 0011 0100₂ = 3 4₁₆ →

Jamia Millia Islamia PYQ 2022
The universal gate is …





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

NAND and NOR are universal; here option is NAND. 

Jamia Millia Islamia PYQ 2022
The inputs of a NAND gate are connected together. The resulting circuit is 





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

NAND with tied inputs gives ¬(A·A)=¬A → NOT gate.

Jamia Millia Islamia PYQ 2022
Exclusive-OR (XOR) logic gates can be constructed from _____ logic gates.





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

 Standard realization uses AND, OR, NOT.

Jamia Millia Islamia PYQ 2022
____ truth table entries are necessary for a four-input circuit.





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

 Number of input combinations = 2^4 = 16. 

Jamia Millia Islamia PYQ 2022
Simplify the Boolean expression (three variables): $ F=\;A'BC\;+\;A'B'C\;+\;ABC'\;+\;A'B'C'\;+\;ABC\;+\;AB'C' $





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

Group terms: - $ABC + ABC' = AB$ - $A'B'C' + AB'C' = B'C'$ - $A'BC + A'B'C = A'C$ Hence $ F = AB \;+\; B'C' \;+\; A'C. $ This is already minimal (no further absorption). $\boxed{F = AB + A'C + B'C'}$

Jamia Millia Islamia PYQ 2022
Minimize the following 3-variable function: $F(A,B,C)=\sum(0,1,6,7)$





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

Minterms 0(000) and 1(001) → pair ⇒ $A'B'$. Minterms 6(110) and 7(111) → pair ⇒ $AB$. So $F = A'B' + AB$ (XNOR, independent of $C$).

Jamia Millia Islamia PYQ 2022
When some unidentified/unknown person/firm sends you mail in a trustworthy/lucrative way asking for sensitive bank and online payment information, this is a case of __?





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

That description matches credential-stealing emails → Phishing.

Jamia Millia Islamia PYQ 2022
Which memory card format is most widely used in smartphones?





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

Smartphones use microSD (Secure Digital family).

Jamia Millia Islamia PYQ 2022
 Which of the following is a popular VoIP application?





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

Skype is a well-known VoIP app.

Jamia Millia Islamia PYQ 2022
Computer language used for Internet is:





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

HTML is the standard markup for web pages.

Jamia Millia Islamia PYQ 2022
Convert the following number to decimal: (1032.2)_4





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

1·4^3 + 0·4^2 + 3·4 + 2 + 2·4^(-1) = 64 + 12 + 2 + 0.5 = 78.5

Jamia Millia Islamia PYQ 2022
Python was conceived in the late ____ by Guido van Rossum.





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

Python was started in 1989 (late 1980s)

Jamia Millia Islamia PYQ 2022
 Which memory must be refreshed many times per second?





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

DRAM cells leak charge and require periodic refresh.

Jamia Millia Islamia PYQ 2022
USB-type storage device is:





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

USB drives are non-volatile external/secondary storage.

Jamia Millia Islamia PYQ 2022
Climate change is one of the most ____ contested environmental debates of our time.





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

hotly — “hotly contested” is the correct collocation.

Jamia Millia Islamia PYQ 2022
Gulf Stream ocean current ____ disrupted? ____ way, Antarctica is a crucial element in this debate.





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

is, either — singular “is” for “current”; phrase “Either way, …”.

Jamia Millia Islamia PYQ 2022
Identify the word which means the same as HEAVING UP.





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

is, either — singular “is” for “current”; phrase “Either way, …”.

Jamia Millia Islamia PYQ 2022
Science is actually doing less than nothing.” Here the word ACTUALLY is





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

adverb — it modifies “is doing”.

Jamia Millia Islamia PYQ 2022
Noun form of INTELLECTUAL is





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Solution



Jamia Millia Islamia PYQ 2022
The verb form of PRESSURE is






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Solution



Jamia Millia Islamia PYQ 2022
 I certainly ______ (help) my colleague if I had been there.





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Solution



Jamia Millia Islamia PYQ 2022
He always ____ (try) to prove that the earth revolves round the sun.





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

 tries  — habitual action (simple present).




Jamia Millia Islamia PYQ 2022
Syam told Sita that she ______ (play) tennis.





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

was playing  — backshift in reported speech.


Jamia Millia Islamia PYQ 2022
The train had left before I ______ (reach) the station.





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution



Jamia Millia Islamia PYQ 2022
I am facing South, I turn right and walk 20 m. Then I turn right again and walk 10 m. Then I turn left and walk 10 m and then turning right walk 20 m. Then I turn right again and walk ___ m. In which direction am I from the starting point?”





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Solution



Jamia Millia Islamia PYQ 2022
Identify the wrong term: 31, 29, 31, 30, 28, 30, 29, 27, 26





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

31→29 (−2), 29→31 (+2), 31→30 (−1), 30→28 (−2), 28→30 (+2), 30→29 (−1), 29→27 (−2), so next should be +2 → 29, not 26.

Jamia Millia Islamia PYQ 2022
If $D=23$, $H=19$, decode 8767.





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

Mapping is $A!\mapsto!26$, $B!\mapsto!25$, … (i.e., value $=27-\text{position}$).
$8!\to!27-8=19=S$, $7!\to!20=T$, $6!\to!21=U$, $7!\to!20=T$.


Jamia Millia Islamia PYQ 2022
If BEAT is written as GIDV, then SOUP may be written as





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

Shifts by +5, +4, +3, +2:
B→G (+5), E→I (+4), A→D (+3), T→V (+2).
Apply to SOUP: S→X (+5), O→S (+4), U→X (+3), P→R (+2) ⇒ XSXR.
This exact result isn’t in the options; closest pattern-wise is option (A) 

Jamia Millia Islamia PYQ 2022
If 213 = 419, 322 = 924, 415 = 16125; then 215 = ?





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

Rule → square 1st & last digits, keep middle same.
213 → 2² 1 3² = 4 1 9; 322 → 3² 2 2² = 9 2 4; 415 → 4² 1 5² = 16 1 25.
So 215 → 2² 1 5² = 4 1 25 = **4125**.

Jamia Millia Islamia PYQ 2022
If A+B: “B is brother of A”, A×B: “B is husband of A”,
A−B: “A is mother of B”, A%B: “A is father of B”.
Which shows Q is grandmother of T?





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

 Q−P ⇒ Q mother of P; P+R ⇒ R brother of P ⇒ Q mother of R;
R%T ⇒ R father of T. Thus Q is mother of (father of T) ⇒ grandmother.

Jamia Millia Islamia PYQ 2022
ARUN : CTWP :: RITA : ?





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

Each letter +2: A→C, R→T, U→W, N→P. RITA +2 → T K V C ⇒ TKVC

Jamia Millia Islamia PYQ 2022
THIN : MCFM :: PRTV : ?





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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

Shifts −7, −5, −3, −1: T→M (−7), H→C (−5), I→F (−3), N→M (−1). Apply to PRTV: P→I, R→M, T→Q, V→U ⇒ **IMQU**.

Jamia Millia Islamia PYQ 2022
If ‘HEALTH’ is written as ‘GSKZDG’, then how will ‘NORTH’ be written in that code?






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Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

Rule = reverse the word, then shift each letter **−1**. HEALTH → (reverse) HTLAEH → (−1) GSKZDG ✓ NORTH → (reverse) HTRON → (−1) GSQNM.


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