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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
If $f(x)=ax^7+bx^3+cx-5$, where $a,b,c$ are real constants, and $f(-7)=7$,
then the range of $f(7)+17\cos x$ is:
Solution
$f(7)=-(f(-7))= -7 + 10 = 27$ (since odd-powered terms change sign). Actually, $f(7)=-f(-7)-10=...$ simplifying gives $f(7)=17$. Then $f(7)+17\cos x = 17 + 17\cos x$. Range = $[17-17,17+17]=[0,34]$.Online Test Series, Information About Examination,
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