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Previous Year Question (PYQs)



The numbers $3, 5, 7, 4$ have frequencies $x, x+4, x-3, x+8$. If their arithmetic mean is $4$, then the value of $x$ is:





Solution

$\text{Mean} = \dfrac{3x + 5(x+4) + 7(x-3) + 4(x+8)}{x + (x+4) + (x-3) + (x+8)} = 4$ $\Rightarrow \dfrac{19x + 33}{4x + 9} = 4$ $\Rightarrow 19x + 33 = 16x + 36$ $\Rightarrow 3x = 3$ $\Rightarrow x = 1$


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