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Delhi University MCA 2020 PYQ

Delhi University MCA PYQ 2020
Find the odd man out: 
1, 4, 27, 16, 125, 36, 216, 64, 729, 100





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Delhi University MCA Previous Year PYQ Delhi University MCA DU MCA 2020 PYQ

Solution

The pattern of the series is 13, 22, 33, 42, 53, 62, 73. ..... 
Odd Term 216.
Delhi University MCA PYQ 2020
An athlete has to cover a distance of 6 Kms in 90 Minutes. He covers two-third of the distance in two-thirds of the total time. To cover the remaining distance in the remaining time, his speed should be____ Km/Hr. ?





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Delhi University MCA Previous Year PYQ Delhi University MCA DU MCA 2020 PYQ

Solution

Total distance = 6 km, Total time = 90 min = 1.5 hr

Distance covered = $\frac{2}{3}\times6=4$ km, Time taken = $\frac{2}{3}\times90=60$ min = 1 hr

Speed in first part = $\dfrac{4}{1}=4$ km/hr

Remaining distance = 2 km, Remaining time = 0.5 hr

Required speed = $\dfrac{2}{0.5}=4$ km/hr

Answer: $\boxed{4\text{ km/hr}}$ ✅

Delhi University MCA PYQ 2020
A and B can complete a work in 15 days. B and C can complete the same work in 20 days. If A, B and C together can finish it in 10 days, then A and C can complete the same work in____days.





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Delhi University MCA Previous Year PYQ Delhi University MCA DU MCA 2020 PYQ

Solution

Let rates be $a,b,c$. Given: $a+b=\tfrac{1}{15}$, $b+c=\tfrac{1}{20}$, $a+b+c=\tfrac{1}{10}$.

Using $(a+b)+(a+c)+(b+c)=2(a+b+c)$:

$\tfrac{1}{15}+(a+c)+\tfrac{1}{20}=\tfrac{1}{5}\ \Rightarrow\ a+c=\tfrac{1}{5}-\left(\tfrac{1}{15}+\tfrac{1}{20}\right)=\tfrac{1}{12}$

Time by $A+C = \dfrac{1}{1/12}=12$ days.

Answer: $\boxed{12\text{ days}}$ ✅

Delhi University MCA PYQ 2020
If 2x = (1024)1/5, what is the value of x ?





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Delhi University MCA Previous Year PYQ Delhi University MCA DU MCA 2020 PYQ

Solution

$2^x=1024^\frac{1}{5}$
$2^x=(2^{10})^{1/5}$
$2^x=2^{10/5}$
$2^x=2^2$
$x=2$

Delhi University MCA PYQ 2020
Two trains each 500 metres long, are running in opposite directions on parallel tracks. If their speeds are 50 km/hr and 40 km/hr respectively, the time taken by the slower train to pass the driver of the faster one is _______seconds





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Delhi University MCA Previous Year PYQ Delhi University MCA DU MCA 2020 PYQ

Solution

Speed of faster train $= 50$ km/h $= 13.89$ m/s

Speed of slower train $= 40$ km/h $= 11.11$ m/s

Relative speed (opposite directions) $= 13.89 + 11.11 = 25$ m/s

Distance to be covered $= 500$ m

Time $= \dfrac{500}{25} = 20$ seconds

Answer: $\boxed{20\text{ seconds}}$ ✅

Delhi University MCA PYQ 2020
The speed of a boat in still water is 12 km/hr and the rate of current is 3 km/hr. The distance travelled downstream in 30 minutes is





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Delhi University MCA Previous Year PYQ Delhi University MCA DU MCA 2020 PYQ

Solution

Speed in still water $= 12$ km/hr

Rate of current $= 3$ km/hr

Downstream speed $= 12 + 3 = 15$ km/hr

Time $= 30$ min $= \dfrac{1}{2}$ hr

Distance $= 15 \times \dfrac{1}{2} = 7.5$ km

Answer: $\boxed{7.5\text{ km}}$ ✅

Delhi University MCA PYQ 2020
Which one of the following is in built data structure of C language?





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Solution

Delhi University MCA PYQ 2020
Which of the following operators in C language has right to left associativity:





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Solution

Delhi University MCA PYQ 2020
The following in C language is valid 
Variable = expression l ? expression 2: expression 3 

It represents a (an)





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Solution

Delhi University MCA PYQ 2020
Which one of the following is incorrect in C language?





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Solution

Delhi University MCA PYQ 2020
The series $$\sum_{n=3}^{\infty}\frac{1}{\,n(\log n)(\log\log n)^{c}\,} $$ converges if
(a) 0<c<1
(b) c>1
(c) -1<c<0
(d) c=1






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Solution

Delhi University MCA PYQ 2020

If the following holds:

$ \lim_{n\to\infty}\frac{u_n}{v_n}=l,\quad u_n>0,\ v_n>0,\ l\ne 0 $ then choose the correct option:

(a) $\sum u_n$ and $\sum v_n$ converge together

(b) $\sum u_n$ diverges and $\sum v_n$ converges

(c) $\sum u_n$ converges and $\sum v_n$ diverges

(d) Neither $\sum u_n$ converges nor $\sum v_n$ diverges






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Solution

Delhi University MCA PYQ 2020





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Delhi University MCA Previous Year PYQ Delhi University MCA DU MCA 2020 PYQ

Solution

Let U and V be vector spaces. 
Then they are isomorphic iff there is a bijection from a basis of U to a basis of V. 
The isomorphism is the basis changer function.
This means that if U and V are finite-dimensional vector spaces, they are isomorphic iff dim(U)=dim(V).
Delhi University MCA PYQ 2020
The condition for the line $x\cos\alpha+y\sin\alpha=p$ to touch the curve $\left(\dfrac{x}{a}\right)^3+\left(\dfrac{y}{b}\right)^3=1$ is $(a\cos\alpha)^t+(b\sin\alpha)^t=p^t$ where $t$ is equal to





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Solution

Delhi University MCA PYQ 2020
If $g$ is Riemann integrable on $[a,b]$ and $f(x)=g(x)$ except for a finite number of points in $[a,b]$, then

 (a) $f$ is Riemann integrable and $\int_a^b f(x)\,dx=\int_a^b g(x)\,dx$

 (b) $f$ is Riemann integrable and $\int_a^b f(x)\,dx<\int_a^b g(x)\,dx$ 

 (c) $f$ is Riemann\text{-}integrable and $\int_a^b f(x)\,dx>\int_a^b g(x)\,dx$

 (d) $f$ is not Riemann\text{-}integrable 





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Solution


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