Let rates be $a,b,c$. Given: $a+b=\tfrac{1}{15}$, $b+c=\tfrac{1}{20}$, $a+b+c=\tfrac{1}{10}$.
Using $(a+b)+(a+c)+(b+c)=2(a+b+c)$:
$\tfrac{1}{15}+(a+c)+\tfrac{1}{20}=\tfrac{1}{5}\ \Rightarrow\ a+c=\tfrac{1}{5}-\left(\tfrac{1}{15}+\tfrac{1}{20}\right)=\tfrac{1}{12}$
Time by $A+C = \dfrac{1}{1/12}=12$ days.
Answer: $\boxed{12\text{ days}}$ ✅
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