AMU MCA Logical Ability and Logical Reasoning Previous Year Question Paper and Solution with PDF

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AMU MCA Previous Year Questions (PYQs)

AMU MCA Logical Ability And Logical Reasoning PYQ

Qus : 1 AMU MCA PYQ

LOGIC: BHFNK :: CLERK : ?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

Pattern: Each letter is moved +2, +2, +2, +2, +2 alphabetically.

CLERK →

C → E

L → N

E → G

R → T

K → M

Qus : 2 AMU MCA PYQ

Statements:

A. All terrorists are guilty.

B. All terrorists are criminals.

Conclusions:

I. Either all criminals are guilty or all guilty are criminals.

II. Some guilty persons are criminals.

III. Generally criminals are guilty.

IV. Crime and guilt go together.

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

From statements: Terrorists ⊆ Guilty and Terrorists ⊆ Criminals.

There must be some guilty persons who are criminals.

Conclusion II follows.

Other conclusions are either vague or not definite.

Qus : 3 AMU MCA PYQ

If P denotes +, Q denotes −, R denotes × and S denotes ÷, which of the following statements is correct?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

$8×8 + 8÷8 − 8 = 64 + 1 − 8 = 57$

Qus : 4 AMU MCA PYQ

X is 5th from right end and Y is 15th from left end. If they interchange their places, Y becomes 24th from left end. Then what is the number of students?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

After interchange, Y is 24th from left. Original position of X = 24 Total students $= 24 + 5 − 1 = 28$

Qus : 5 AMU MCA PYQ

At the time of marriage a man was 6 years older than his wife but 12 years after the marriage he was $\frac{6}{5}$ times the age of his wife. What were their ages in years at the time of marriage?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

Let wife’s age at marriage = $x$ Man’s age = $x + 6$ After 12 years: $\frac{x + 18}{x + 12} = \frac{6}{5}$ $5x + 90 = 6x + 72$ $x = 18$ Man’s age = $24$

Qus : 6 AMU MCA PYQ

Statements:

A. Some books are pens.

B. No pen is pencil.

Conclusions:

I. Some pens are books.

II. Some pencils are books.

III. Some books are not pencils.

IV. All pencils are books.

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

From statement A → I follows. From statement B → books (which are pens) cannot be pencils → III follows.

Qus : 7 AMU MCA PYQ

If ‘A $ B’ means ‘A is the father of B’, ‘A * B’ means ‘A is the mother of B’, ‘A @ B’ means ‘A is the wife of B’, then which of the following means ‘M is the grandmother of N’?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

M * T ⇒ M is mother of T

T $ R ⇒ T is father of R

So M is grandmother of R ✅

R @ N ⇒ R is wife of N (female), so N is husband of R

This does not make R parent of N. ❌

Check (d) M * R @ T @ N

M * R ⇒ M is mother of R

R @ T ⇒ R is wife of T (so T is husband of R)

T @ N ⇒ T is wife of N (impossible here: T already husband in previous step) ❌

Check (c) M $ R $ T @ N

M $ R ⇒ M is father of R (male) ❌ (grandmother must be female)

So only valid form is (a): M * T $ N @ R

M * T ⇒ M is mother of T

T $ N ⇒ T is father of N

So M is grandmother of N ✅

(Last part “N @ R” just adds N is wife of R, doesn’t break grandmother relation)

Qus : 8 AMU MCA PYQ

If ‘P F Q’ means ‘P is father of Q’; ‘P M Q’ means ‘P is mother of Q’; ‘P S Q’ means ‘P is sister of Q’, then how is D related to N in ‘N M A F B S D’?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

M A → N is mother of A

A F B → A is father of B

B S D → B is sister of D

Qus : 9 AMU MCA PYQ

A man walks 1 km towards East and then he turns to South and walks 5 km. Again he turns to East and walks 2 km, after this he turns to North and walks 9 km. Now, how far is he from his starting point?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

Take start as (0,0).

East 1 → (1,0)

South 5 → (1,-5)

East 2 → (3,-5)

North 9 → (3,4)

Distance from start

$= \sqrt{3^2 + 4^2} = 5$ km

Qus : 10 AMU MCA PYQ

Pointing to a gentleman, Deepak said, “His only brother is the father of my daughter’s father.” How is the gentleman related to Deepak?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

“My daughter’s father” = Deepak.

So “father of my daughter’s father” = Deepak’s father.

Gentleman’s only brother = father of Deepak = Deepak’s father.

So gentleman is brother of Deepak’s father = Deepak’s uncle.

Qus : 11 AMU MCA PYQ

Study the following information carefully and answer the question given below:

In a certain code language:

‘sovian attract class’ is written as ‘chi ki pa’,

‘she are honor sovian’ is written as ‘din sa chi ta’,

‘team teaches ink class’ is written as ‘la ja pa ha’ and

‘she are team’ is written as ‘din sa ha’.

Which of the following may be the code for ‘are she ink class’?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

From ‘she are team’ = din sa ha

and ‘she are honor sovian’ = din sa chi ta

Common = din, sa ⇒ codes for she and are.

From ‘sovian attract class’ = chi ki pa

and ‘team teaches ink class’ = la ja pa ha

Common = pa ⇒ code for class.

In ‘team teaches ink class’, remaining codes (la, ja) are for teaches and ink.

So “are she ink class” must include: din, sa, pa, and (la or ja).

Qus : 12 AMU MCA PYQ

Krishna runs 20m towards East and turns to right, runs 10m and turns to right, runs 9m and again turns to right, runs 5m and then turns to left, runs 12m and finally turns to right and runs 6m. Now which direction is he facing?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

Start facing East.

Right → South

Right → West

Right → North

Left → West

Right → North

So final facing direction = North.

Qus : 13 AMU MCA PYQ

The place of Meena is 15th from the top and bottom both. How many students in her class?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

Total students = 15 + 15 − 1 = 29

Qus : 14 AMU MCA PYQ

Choose the option which has the same relationship as the given pair:

Painting : Artist

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

Painting is created by Artist.

Poem is created by Poet.

Qus : 15 AMU MCA PYQ

If A is to the South of B and C is to the East of B, in what direction is A with respect to C?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

Place B at center.

A is South of B.

C is East of B.

So from C, A lies towards South-West.

Qus : 16 AMU MCA PYQ

A clock is so placed that at 12:00 noon its minute hand points towards North-East. In which direction does its hour hand point at 1:30 p.m.?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

At 12:00, minute hand at 12 points North-East.

So 12 position = North-East.

At 1:30, hour hand is at 1.5 position = 45 degrees clockwise from 12.

North-East + 45 degrees = East.

Qus : 17 AMU MCA PYQ

A clock is so placed that at 12:00 noon its minute hand points towards North-East. In which direction does its hour hand point at 1:30 p.m.?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

At 12:00, minute hand at 12 points North-East.

So 12 position = North-East.

At 1:30, hour hand is at 1.5 position = 45 degrees clockwise from 12.

North-East + 45 degrees = East.

Qus : 18 AMU MCA PYQ

In a zoo, there are rabbits and pigeons. If heads are counted there are 200 in all and if legs are counted there are 580 in all. How many pigeons are there in the zoo?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

Let rabbits = r, pigeons = p

Heads:

r + p = 200

Legs:

4r + 2p = 580

Multiply first equation by 2:

2r + 2p = 400

Subtract:

2r = 180 → r = 90

So p = 200 − 90 = 110

Qus : 19 AMU MCA PYQ

Six persons A, B, C, D, E and F are sitting in two rows, three in each.

E is not at the end of any row.

D is second to the left of F.

C, the neighbour of E, is sitting diagonally opposite to D.

B is the neighbour of F.

Which of the following are sitting diagonally opposite to each other?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

Arranging step-by-step as per conditions, the only pair sitting diagonally opposite is A and C.

Qus : 20 AMU MCA PYQ

In how many of the given years was the production of fertilizers more than the average production of the given years?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

Total = 25 + 40 + 60 + 45 + 65 + 50 + 75 + 80 = 440

Average = 440 / 8 = 55

Above average years: 2007 (60), 2009 (65), 2011 (75), 2012 (80) → 4 years

Qus : 21 AMU MCA PYQ

The average production of 2006 and 2007 was exactly equal to the average production of which of the following pairs of years?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

Average of 2006 and 2007 = (40 + 60) / 2 = 50

Check options:

2008 and 2010 → (45 + 50) / 2 = 47.5

2009 and 2010 → (65 + 50) / 2 = 57.5

2005 and 2009 → (25 + 65) / 2 = 45

2005 and 2011 → (25 + 75) / 2 = 50

Qus : 22 AMU MCA PYQ

What was the percentage decline in the production of fertilizers from 2007 to 2008?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

Decline = 60 − 45 = 15

Percentage decline = (15 / 60) × 100 = 25%

Qus : 23 AMU MCA PYQ

In which year was the percentage increase in production as compared to the previous year the maximum?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

2006 over 2005: (40−25)/25 ×100 = 60%

2007 over 2006: (60−40)/40 ×100 = 50%

2009 over 2008: (65−45)/45 ×100 ≈ 44.44%

2012 over 2011: (80−75)/75 ×100 ≈ 6.67%

Maximum increase = 2006

Qus : 24 AMU MCA PYQ

Out of 6 consonants and 3 vowels, how many words of 3 consonants and 2 vowels can be formed?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

Choose consonants: $^6C_3 = 20$

Choose vowels: $^3C_2 = 3$

Arrange 5 selected letters: $5! = 120$

Total words $= 20 \times 3 \times 120 = 7200$

Qus : 25 AMU MCA PYQ

Arrange the following words according to dictionary arrangement:

1.Episode

2.Epitaxy

3.Epitome

4.Epilogue

5.Epigene

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

All words start with Epi.

Compare next letters:

Epigene (g)

Epilogue (l)

Episode (s)

Epitaxy (t a)

Epitome (t o)

Alphabetical order:

Epigene → Epilogue → Episode → Epitaxy → Epitome

So order = 5, 4, 1, 2, 3

Qus : 26 AMU MCA PYQ

Indian Cinema Halls should not be allowed to show foreign movies.

Assumptions:

I. Foreign movies are responsible for falling moral values.

II. Indian movies are responsible for falling moral values.

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2020 PYQ

Solution

The statement suggests foreign movies cause harm (moral decline), otherwise there is no reason to ban them.

Thus Assumption I is implicit.

Assumption II is not required.

Qus : 27 AMU MCA PYQ

Renuka started walking from her house. She first walked for 3 km towards West, then she turned towards North and moved 4 km in that direction. How far is Renuka from her house?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2020 PYQ

Solution

She moves 3 km West and 4 km North.

Distance from house:

$\sqrt{3^2+4^2}=5$ km

Direction = North-West

Qus : 28 AMU MCA PYQ

X is to the South-West of Y. L is to the East of X and South-East of Y and M is to the North of L in line with XY. In which direction of Y is M located?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2020 PYQ

Solution

Placing positions according to directions and tracing movement, M lies directly above (North of) Y.

Qus : 29 AMU MCA PYQ

Choose the correct alternative that will constitute the same pattern:

98, 90, 82, 74, __, 58

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2020 PYQ

Solution

Pattern: subtract 8 each time

98 − 8 = 90

90 − 8 = 82

82 − 8 = 74

74 − 8 = 66

66 − 8 = 58

Qus : 30 AMU MCA PYQ

Find the next number in the series:

2, 9, 28, 65, __

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2020 PYQ

Solution

Solution:

2 = 1³ + 1

9 = 2³ + 1

28 = 3³ + 1

65 = 4³ + 1

Next = 5³ + 1 = 125 + 1 = 126

Qus : 31 AMU MCA PYQ

A, B, C, D, E, F and G are travelling in three different vehicles I, II and III. There are at least two passengers in each vehicle and each vehicle has passengers of both the sexes. There are two engineers, two doctors and three teachers among them. C is a lady doctor and she does not travel with the pair of sisters A and F. B is a male engineer and travels with only G, a teacher in vehicle I. D is a male doctor. Two persons belonging to same profession do not travel in the same vehicle. A is not an engineer and travels in vehicle II. In which vehicle does C travel?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2020 PYQ

Solution

Vehicle I → B (Engineer) and G (Teacher)

Vehicle II → A (Teacher), F (Teacher)

C cannot travel with A and F (given).

Two same profession cannot travel together.

Since D is doctor and C is doctor, they cannot be in same vehicle.

After proper arrangement, C must travel in Vehicle III.

Qus : 32 AMU MCA PYQ

If × = +, + = −, − = ÷ and ÷ = ×, then find the solution of:

8 ÷ 2 × 12 − 3 + 9

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2020 PYQ

Solution

Replace symbols:

8 × 2 + 12 ÷ 3 − 9

Now apply BODMAS:

8 × 2 = 16

12 ÷ 3 = 4

16 + 4 − 9 = 11

Qus : 33 AMU MCA PYQ

Choose the correct alternative:

7, 15, 32, __, 138, 281

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2020 PYQ

Solution

Pattern: ×2 + increasing numbers

7 × 2 + 1 = 15

15 × 2 + 2 = 32

32 × 2 + 3 = 67

67 × 2 + 4 = 138

138 × 2 + 5 = 281

Qus : 34 AMU MCA PYQ

The missing number in the series 40, 120,60, 180, 90,. lsis:

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2020 PYQ

Solution

Pattern: ×3, ÷2 alternately

40 × 3 = 120

120 ÷ 2 = 60

60 × 3 = 180

180 ÷ 2 = 90

90 × 3 = 270

270 ÷ 2 = 135

Qus : 35 AMU MCA PYQ

Salim, the son of Murad, is married to Sanna. Sanna’s sister Jabeen is married to Ayaan, the brother of Salim. How is Jabeen related to Murad?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2021 PYQ

Solution

Salim is Murad’s son. Ayaan is Salim’s brother → also Murad’s son. Jabeen is married to Ayaan → wife of Murad’s son. So Jabeen is Murad’s daughter-in-law.

Qus : 36 AMU MCA PYQ

Santosh goes first 7 km North, then turns left and moves 10 km, again turns left and moves 7 km. How far is he from starting point?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2021 PYQ

Solution

North 7 → West 10 → South 7 Final position: 10 km West of starting point Distance = 10 km

Qus : 37 AMU MCA PYQ

Neeta starting from point X walked 5 km West, turned left walked 2 km, again turned left walked 7 km. In which direction is she from X?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2021 PYQ

Solution

West 5 → South 2 → East 7

Net: 2 km East and 2 km South

Direction = South-East

Qus : 38 AMU MCA PYQ

Find the missing in the following:

ACE, GIK, _____, SUN

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2021 PYQ

Solution

Pattern: Each term letters increase by +2

A C E

G I K

Next: M O Q

S U N (pattern continues)

Qus : 39 AMU MCA PYQ

Find the missing sequence:

25, 49, 121, 169, _____

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2021 PYQ

Solution

Squares of prime numbers:

$5^2 = 25$

$7^2 = 49$

$11^2 = 121$

$13^2 = 169$

Next prime = 17

$17^2 = 289$

Qus : 40 AMU MCA PYQ

Select the pair that has the same relationship as the original pair

East : Orient

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2021 PYQ

Solution

Orient means East.

Occident means West.

Same synonym relationship.

Qus : 41 AMU MCA PYQ

Find the missing sequence 1, 1, 2, 3, ____, 8, 13

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2021 PYQ

Solution

This is Fibonacci sequence

1, 1, 2, 3, 5, 8, 13

Qus : 42 AMU MCA PYQ

Find the missing B : 16 :: D : ?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2021 PYQ

Solution

B = 2 → $2^4 = 16$ D = 4 → $4^4 = 256$

Qus : 43 AMU MCA PYQ

The number that must be added to the terms of the ratio $11 : 29$ to make it equal to $11 : 20$ is:

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

Let the required number be $x$ $\frac{11 + x}{29 + x} = \frac{11}{20}$ $20(11 + x) = 11(29 + x)$ $220 + 20x = 319 + 11x$ $9x = 99$ $x = 11$

Qus : 44 AMU MCA PYQ

The least number which when divided by 9, 10 and 15 leaves the remainders 4, 5 and 10 respectively is:

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

Required number $= \text{LCM}(9,10,15) - 5$ $\text{LCM}(9,10,15) = 90$ $90 - 5 = 85$

Qus : 45 AMU MCA PYQ

In a class the ratio of boys and girls is 4 : 3. If 7 girls join the class, the ratio of boys and girls becomes 3 : 4. Then the number of boys in the class is:

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

Initial ratio $= 4 : 3$ Let boys $= 4x$, girls $= 3x$ After 7 girls join: $\frac{4x}{3x + 7} = \frac{3}{4}$ $16x = 9x + 21$ $7x = 21$ $x = 3$ Number of boys $= 4x = 12$

Qus : 46 AMU MCA PYQ

A century leap year is divisible by:

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

A century year is a leap year only if it is divisible by 400.

Qus : 47 AMU MCA PYQ

My age becomes half that of my brother’s if we simply add 2 years to his present age. If I am 25 years old today, my brother will be:

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

Let brother’s present age $= x$ According to question: $25 = \frac{x + 2}{2}$ $x + 2 = 50$ $x = 48$

Qus : 48 AMU MCA PYQ

0.5 of a number is equal to 0.07 of another. The ratio of the numbers is:

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

Let the numbers be $x$ and $y$ $0.5x = 0.07y$ $\frac{x}{y} = \frac{0.07}{0.5}$ $\frac{x}{y} = \frac{7}{50}$ Ratio $= 7 : 50$

Qus : 49 AMU MCA PYQ

In what time will a sum of money double itself at $6\ \frac{1}{4}%$ p.a. simple interest?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

For simple interest to double: $T = \frac{100}{R}$ Here $R = 6.25$ $T = \frac{100}{6.25} = 16$ years

Qus : 50 AMU MCA PYQ

At simple interest, a sum doubles after 20 years. The rate of interest per annum is:

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

For doubling in simple interest: $R = \frac{100}{T}$ $R = \frac{100}{20} = 5%$

Qus : 51 AMU MCA PYQ

In what time will the simple interest on Rs. 780 at 5% be equal to the simple interest on Rs. 600 at $6\ \frac{1}{2}%$?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

Simple interest $= \frac{PRT}{100}$ $\frac{780 \times 5 \times T}{100} = \frac{600 \times 6.5 \times T}{100}$ $39T = 39T$ True for all $T$

Qus : 52 AMU MCA PYQ

Oranges are bought at the rate of 10 for Rs. 25 and sold at the rate of 9 for Rs. 25. The profit is:

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

Cost price per orange $= \frac{25}{10} = 2.5$ Selling price per orange $= \frac{25}{9}$ Profit per orange $= \frac{25}{9} - 2.5 = \frac{25 - 22.5}{9} = \frac{2.5}{9}$ Profit % $= \frac{\frac{2.5}{9}}{2.5} \times 100 = \frac{100}{9} = 11\ \frac{1}{9}%$

Qus : 53 AMU MCA PYQ

A man rows to a place 48 km distant and back in 14 hours. He finds that he can row 4 km with the stream in the same time as 3 km against the stream. The rate of the stream is:

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

Let speed in still water $= u$, stream speed $= v$ $\frac{4}{u+v} = \frac{3}{u-v}$ $4(u-v) = 3(u+v)$ $u = 7v$ Total time: $\frac{48}{u+v} + \frac{48}{u-v} = 14$ Substitute $u = 7v$: $\frac{48}{8v} + \frac{48}{6v} = 14$ $\frac{6}{v} + \frac{8}{v} = 14$ $\frac{14}{v} = 14 \Rightarrow v = 1$

Qus : 54 AMU MCA PYQ

The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

Difference (2 years) $= P\left(\frac{R}{100}\right)^2$ $1 = P\left(\frac{4}{100}\right)^2$ $1 = P \times \frac{16}{10000}$ $P = \frac{10000}{16} = 625$

Qus : 55 AMU MCA PYQ

A train leaves Delhi at 4.10 p.m. and reaches Aligarh at 7.25 p.m. The average speed of the train is 40 km/hr. What is the distance from Delhi to Aligarh?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

Time taken $= 3\ \text{hours}\ 15\ \text{minutes} = 3.25\ \text{hours}$ Distance $= \text{Speed} \times \text{Time}$ $= 40 \times 3.25 = 130\ \text{km}$

Qus : 56 AMU MCA PYQ

Sonu’s age is $\frac{2}{3}$ of Manu’s. After 5 years Sonu will be 45 years old. Manu’s present age is:

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

Sonu’s present age $= 45 - 5 = 40$ Given $40 = \frac{2}{3}$ of Manu’s age Manu’s age $= 40 \times \frac{3}{2} = 60$ years

Qus : 57 AMU MCA PYQ

A person travelled a distance of 50 km in 8 hours. He covered a part of the distance on foot at the rate of 4 km/hr and a part on a bicycle at the rate of 10 km/hr. How much distance did he travel on foot?

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AMU MCA Previous Year PYQ AMU MCA AMU MCA 2024 PYQ

Solution

$\frac{x}{4} + \frac{50-x}{10} = 8$ Multiply by 20: $5x + 2(50-x) = 160$ $5x + 100 - 2x = 160$ $3x = 60 \Rightarrow x = 20$

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