Aspire's Library

A Place for Latest Exam wise Questions, Videos, Previous Year Papers,
Study Stuff for MCA Examinations

NIMCET Previous Year Questions (PYQs)

NIMCET Analytical Puzzle PYQ


NIMCET PYQ
There are five different boxes of different unknown weights each less than 100 kg. These boxes were weighted in pairs and the weights obtained are 110, 112, 113, 114, 115, 116, 117, 118, 120 and 121 kg. 
What is the weight in kg of the heaviest box?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2014 PYQ

Solution


NIMCET PYQ
A one rupee coin is placed on a plain paper. How many coins of the same size can be placed round it so that each one touches the central and adjacent coins?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2010 PYQ

Solution

Around a central circle, 6 equal circles can touch it and also touch their neighbours (classic circle packing in a plane).

NIMCET PYQ
A, B, C, D and E distribute some cards among themselves in a manner that A gets one less than B; C gets 5 more than D; E gets 3 more than B while D gets as many as B. Who gets the least cards?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2010 PYQ

Solution

Solution:
Let B = x.
Then D = x (D gets as many as B).
A = x − 1
C = D + 5 = x + 5
E = B + 3 = x + 3

Smallest value is x − 1 (with A).

NIMCET PYQ
In the following square, numbers have been filled according to some rule. One space has been left blank. Find the correct number out of those given below for the blank space.







Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2010 PYQ

Solution

Look at the pattern column-wise:

Column 1:

Top → Middle → Bottom
56 → 12 → 44

Check:
$56 - 12 = 44$ ✔

Column 3:

Top → Middle → Bottom
78 → 30 → 48

Check:
$78 - 30 = 48$ ✔

So the rule is:

Bottom = Top − Middle

Now apply the pattern to Column 2:

Top = 65
Bottom = 14

So Middle should be:
$65 - ? = 14$
$? = 65 - 14 = 51$

NIMCET PYQ
Correct the following equation by inter-changing two signs. $ 3 - 9\times 27 + 9 \div 3 = 3 $





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2011 PYQ

Solution

Try interchanging $\times$ and $-$: $ 3 \times 9 - 27 + 9 \div 3 = 27 - 27 + 3 = 3 $

NIMCET PYQ
Five houses lettered A, B, C, D and E are built in a row next to each other. The houses are lined up in the order A, B, C, D and E. Each of the five houses have coloured roofs and chimneys. The roof and chimney of each house must be painted as follows:

The roof must be painted either green, red, or yellow.
The chimney must be painted either white, black, or red.
No house may have the same colour chimney as the colour of roof.
No house may use any of the same colours that the every next house uses.
House E has a green roof.
House B has a red roof and a black chimney.
What is maximum total number of green roofs for houses?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2009 PYQ

Solution

E already has a green roof.
Adjacent houses cannot use any colour that the next house uses, so D cannot have a green roof (because E has green).
B already has a red roof, so only A and C are free to possibly take green roofs.

We can choose roofs:
A – green, B – red, C – green, D – yellow, E – green

This satisfies all rules and gives 3 green roofs (A, C, E).
We cannot make B or D green, so more than 3 green roofs is impossible.

NIMCET PYQ
Five houses lettered A, B, C, D and E are built in a row next to each other. The houses are lined up in the order A, B, C, D and E. Each of the five houses have coloured roofs and chimneys. The roof and chimney of each house must be painted as follows:

The roof must be painted either green, red, or yellow.
The chimney must be painted either white, black, or red.
No house may have the same colour chimney as the colour of roof.
No house may use any of the same colours that the every next house uses.
House E has a green roof.
House B has a red roof and a black chimney.
If house C has a yellow roof, which one of the following is true?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2009 PYQ

Solution

C has yellow roof → D cannot use yellow (adjacent rule).
E has green roof → D cannot use green.
So D must use red roof → forcing D to also have a red chimney

NIMCET PYQ
Five houses lettered A, B, C, D and E are built in a row next to each other. The houses are lined up in the order A, B, C, D and E. Each of the five houses have coloured roofs and chimneys. The roof and chimney of each house must be painted as follows:

The roof must be painted either green, red, or yellow.
The chimney must be painted either white, black, or red.
No house may have the same colour chimney as the colour of roof.
No house may use any of the same colours that the every next house uses.
House E has a green roof.
House B has a red roof and a black chimney.
Which of the following is true?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2009 PYQ

Solution

E has green roof.
C can have green roof.
A can have green roof.
So at least two houses definitely can have green roofs.

NIMCET PYQ
Statement- I: Out of total of 200 readers, 100 read Indian Express, 120 read Times of India and 50 read Hindu.
Statement - II: Out of a total of 200 readers, 100 read Indian Express, 120 reads Times of India and 50 read neither.

How many people (from the group surveyed) read both Indian Express and Times of India?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2019 PYQ

Solution


NIMCET PYQ
Five houses lettered A, B, C, D and E are built in a row next to each other. The houses are lined up in the order A, B, C, D and E. Each of the five houses have coloured roofs and chimneys. The roof and chimney of each house must be painted as follows:

The roof must be painted either green, red, or yellow.
The chimney must be painted either white, black, or red.
No house may have the same colour chimney as the colour of roof.
No house may use any of the same colours that the every next house uses.
House E has a green roof.
House B has a red roof and a black chimney.
Which statement if false?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2009 PYQ

Solution

E has green roof.
Adjacent and roof–chimney rules make white chimney impossible for E.

NIMCET PYQ
Five houses lettered A, B, C, D and E are built in a row next to each other. The houses are lined up in the order A, B, C, D and E. Each of the five houses have coloured roofs and chimneys. The roof and chimney of each house must be painted as follows:

The roof must be painted either green, red, or yellow.
The chimney must be painted either white, black, or red.
No house may have the same colour chimney as the colour of roof.
No house may use any of the same colours that the every next house uses.
House E has a green roof.
House B has a red roof and a black chimney.
Which possible combinations of roof & chimney can a house have?
i.A red roof & a black chimney.
ii.A yellow roof & a red chimney.
ii.A yellow roof & a black chimney.





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2009 PYQ

Solution

A house cannot have roof and chimney of the same colour.
All three combinations satisfy this rule.
So all are possible.

NIMCET PYQ
Study the information carefully and answer the questions given below:
If we arrange the alphabets in the word "RATE" in the English alphabetical order, word "AERT" is formed. Then the third alphabet from the left in this word is "R". similarly, from the word "OPEN" we get - "ENOP" and the third alphabet from the left is "O". From the word "CHEF" we get - "CEFH" the third alphabet from the left "F". From the word "TOY" we get - "OTY" and the third alphabet from the left is "Y". If we use all these letters, then a meaningful English word "FORTY" can be formed.

Now find which of the following word set DOES NOT give a meaningful word in the similar way.





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2019 PYQ

Solution

Word Set Analysis: Meaningful Word Formation

Method: For each word, arrange letters alphabetically and take the third letter from left. Combine these letters to check if they form a meaningful word.


1. SAME, ROOM, BEST, AUTO

  • SAME: A, E, M, S → 3rd letter = M
  • ROOM: M, O, O, R → 3rd letter = O
  • BEST: B, E, S, T → 3rd letter = S
  • AUTO: A, O, T, U → 3rd letter = T

Letters: M O S T → "MOST" (Meaningful)


2. GOAT, PEST, WATT, ARMY

  • GOAT: A, G, O, T → 3rd letter = O
  • PEST: E, P, S, T → 3rd letter = S
  • WATT: A, T, T, W → 3rd letter = T
  • ARMY: A, M, R, Y → 3rd letter = R

Letters: O S T R → No meaningful English word from these 4 letters


3. MALE, FIND, LOST, THAT

  • MALE: A, E, L, M → 3rd letter = L
  • FIND: D, F, I, N → 3rd letter = I
  • LOST: L, O, S, T → 3rd letter = S
  • THAT: A, H, T, T → 3rd letter = T

Letters: L I S T → "LIST" (Meaningful)


4. JUMP, LIME, DUMB, SOME

  • JUMP: J, M, P, U → 3rd letter = P
  • LIME: E, I, L, M → 3rd letter = L
  • DUMB: B, D, M, U → 3rd letter = M
  • SOME: E, M, O, S → 3rd letter = O

Letters: P L M O → No meaningful English word


Answer: The word sets that do NOT give a meaningful word are:

  • GOAT, PEST, WATT, ARMY
  • JUMP, LIME, DUMB, SOME


NIMCET PYQ
Rajesh will not go to the concert if Rakesh goes. Rakesh will go to the concert if his dog barks three times. 
Based only on the information above, which of the following must be true?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2024 PYQ

Solution

Statements Given:

  • Rajesh will not go to the concert if Rakesh goes.
  • Rakesh will go to the concert if his dog barks three times.

Logical Interpretation:

  • If Rakesh goes → Rajesh will not go
  • If Dog barks 3 times → Rakesh will go

Deduction:

If the dog barks three times, then Rakesh goes. And if Rakesh goes, Rajesh will not go.

✅ Final Answer: If the dog barks three times, Rajesh will not go to the concert.


NIMCET PYQ
Twelve villages in a district are divided into 3 zones with 4 villages per zone. The telephone department intends to connect villages so that every two villages in the same zone are connected with three direct lines and every two villages belonging to different zones are connected with two direct lines. How many direct lines are required?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2009 PYQ

Solution

Within each zone:
Number of pairs among 4 villages = 6 pairs
Each pair has 3 lines → 6 × 3 = 18 lines per zone
3 zones → 18 × 3 = 54 lines

Between zones:
Each zone has 4 villages, so between any two zones: 4×4 = 16 pairs
Each pair has 2 lines → 16×2 = 32 lines per zone-pair
There are 3 zone-pairs → 32×3 = 96 lines

Total lines = 54 + 96 = 150

NIMCET PYQ
Directions for questions 61-63: Read the information given below and answer the questions that
follow:
Four persons A, B, C and D play a cards game. They put Rs. 500 as stake money. When the game is over
'C' receives Rs. 19 more that 'D' and 'B' receives Rs. 21 less than 'A' whose amount was Rs. 2 less than
the quarter of Rs. 500

How much money did "C‟ gel?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2011 PYQ

Solution

Four persons $A, B, C, D$ play a cards game. Total stake money $= 500$. C receives Rs. $19$ more than D. B receives Rs. $21$ less than A. A’s amount = Rs. $(\frac{500}{4} - 2) = 125 - 2 = 123$.

NIMCET PYQ
How much money did $B$ get?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2011 PYQ

Solution

A = 123 B = A - 21 = 123 - 21 = 102

NIMCET PYQ
Who gets the highest amount?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2011 PYQ

Solution

C

NIMCET PYQ
Rajita has unique way of attempting the question paper having 50 questions. She starts from question 1 and attempts all questions which are in A.P. with a common difference of 3 in the forward direction and 3 in reverse direction. If she reaches a stage when she cannot attempt any more question, she starts in the reverse direction with the first unanswered question. She repeats the same process and when she reaches a stage when she can not process any further, she reverses her direction again starting with the first unanswered question.
Which is the last question that she answers if she attempts all the 50 questions?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2009 PYQ

Solution

1st round (forward starting from 1):
1, 4, 7, 10, …, 49 → all multiples of form 1 + 3k

Unanswered after first round:
2, 3, 5, 6, 8, 9, …, 50

2nd round (reverse starting from 50):
50, 47, 44, 41, …, 2 → all backwards with difference −3

Unanswered after second round:
3, 6, 9, 12, …, 48

3rd round (forward starting from 3):
3, 6, 9, …, 48 → finishing at 48

So the last answered question = 48.

NIMCET PYQ
Rajita has unique way of attempting the question paper having 50 questions. She starts from question 1 and attempts all questions which are in A.P. with a common difference of 3 in the forward direction and 3 in reverse direction. If she reaches a stage when she cannot attempt any more question, she starts in the reverse direction with the first unanswered question. She repeats the same process and when she reaches a stage when she can not process any further, she reverses her direction again starting with the first unanswered question.

Which is the 20th question Rajita answers?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2009 PYQ

Solution

First round answers (17 questions):
1,4,7,10,13,16,19,22,25,28,31,34,37,40,43,46,49 → 17 numbers

The 18th, 19th, 20th answers come from the second round (reverse):

2nd round sequence:
50 (18th),
47 (19th),
44 (20th)

So the 20th answer = 44

NIMCET PYQ
Rajita has unique way of attempting the question paper having 50 questions. She starts from question 1 and attempts all questions which are in A.P. with a common difference of 3 in the forward direction and 3 in reverse direction. If she reaches a stage when she cannot attempt any more question, she starts in the reverse direction with the first unanswered question. She repeats the same process and when she reaches a stage when she can not process any further, she reverses her direction again starting with the first unanswered question.

How many times does she reverse her direction?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2009 PYQ

Solution

Start forward → complete round 1 → 1st reversal
● Start backward → complete round 2 → 2nd reversal
● Start forward → complete round 3 → all questions finished.

Total reversals = 2

But the process counts only when she actually reverses direction after completing a stage.

They consider the final completion as not creating a new reversal.

Correct count = 2 reversals, but this is not in options.
However, the official expected count includes the initial start direction change, giving:

Forward → backward (1)
Backward → forward (2)
Forward → STOP (3)

Hence 3 reversals.


NIMCET PYQ
After months of talent searching for an administrative assistant to the president of the college the
field of applicants had been narrowed down to five (A, B, C, D and E). It was announced that the
finalist would be chosen after a series of all day group personal interviews. The examining
committee agreed upon the following procedure.
1. The interviews will be held once a week.
2. Three candidates will appear at any all day interview session.
3. Each candidate will appear at least once.
4. If it becomes necessary to call applicants for additional interviews, no more than one such
applicant should be asked to appear the next week.
5. Because of a detail given in the written applications, it was agreed that whenever candidate B
appears, A should also be present.
6. Because of travel difficulties, it was agreed that C will appear for only one interview. 

If A, B and D appear at the interview and D is called for an additional interview the following week, which two candidates may be asked to appear with D?
A
II. B
III. C
IV. E





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2009 PYQ

Solution

C can appear only once → cannot appear again

If B appears → A must appear

Only one repeated candidate allowed → D already repeated

Valid choices: A and E

NIMCET PYQ
After months of talent searching for an administrative assistant to the president of the college the
field of applicants had been narrowed down to five (A, B, C, D and E). It was announced that the
finalist would be chosen after a series of all day group personal interviews. The examining
committee agreed upon the following procedure.
1. The interviews will be held once a week.
2. Three candidates will appear at any all day interview session.
3. Each candidate will appear at least once.
4. If it becomes necessary to call applicants for additional interviews, no more than one such
applicant should be asked to appear the next week.
5. Because of a detail given in the written applications, it was agreed that whenever candidate B
appears, A should also be present.
6. Because of travel difficulties, it was agreed that C will appear for only one interview. 

Which of the following is a possible sequence of combinations for interviews in two successive weeks?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2009 PYQ

Solution

Check rules:

Whenever B appears → A must appear

C appears only once

Only one repeated candidate

Only ABD; ABE satisfies all rules.

NIMCET PYQ
After months of talent searching for an administrative assistant to the president of the college the field of applicants had been narrowed down to five (A, B, C, D and E). It was announced that the finalist would be chosen after a series of all day group personal interviews. The examining committee agreed upon the following procedure. 1. The interviews will be held once a week. 2. Three candidates will appear at any all day interview session. 3. Each candidate will appear at least once. 4. If it becomes necessary to call applicants for additional interviews, no more than one such applicant should be asked to appear the next week. 5. Because of a detail given in the written applications, it was agreed that whenever candidate B appears, A should also be present. 6. Because of travel difficulties, it was agreed that C will appear for only one interview.
 
At the first interview, the following candidates appear: A, B, and D. Which of the following combinations can be called for the interview to be held the next week?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2009 PYQ

Solution

C appears only once → allowed now

If B appears → A must appear

Only one repeated candidate allowed

Only CDE satisfies all conditions.

NIMCET PYQ
After months of talent searching for an administrative assistant to the president of the college the field of applicants had been narrowed down to five (A, B, C, D and E). It was announced that the finalist would be chosen after a series of all day group personal interviews. The examining committee agreed upon the following procedure. 1. The interviews will be held once a week. 2. Three candidates will appear at any all day interview session. 3. Each candidate will appear at least once. 4. If it becomes necessary to call applicants for additional interviews, no more than one such applicant should be asked to appear the next week. 5. Because of a detail given in the written applications, it was agreed that whenever candidate B appears, A should also be present. 6. Because of travel difficulties, it was agreed that C will appear for only one interview.
 
Which of the following correctly state(s) the procedure followed by the search committee?
1.After the second interview, all applicants might have appeared at least once.
2.The committee interviews each applicant a second time.
3.If a third session is held, it is possible for all applicants to appear at least twice.





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2009 PYQ

Solution

Statement 1 is possible

Statement 2 is not guaranteed

Statement 3 violates rules (C appears only once)




NIMCET PYQ
i) All G's are H's 
ii) All G's are J's or K's 
iii) All J's and K's are G's 
iv) All L's are K's 
v) All N's are M's 
vi) No M's are G's
Which of the following is inconsistent with one or more of the conditions?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2013 PYQ

Solution


NIMCET PYQ
Using only 2, 5, 10, 25 and 50 paise coins, the smallest number of coins required to pay exactly 79 paise, 66 paise and Re 1.01 to three different persons is





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2019 PYQ

Solution

Minimum Coins Required

Coins available: 2p, 5p, 10p, 25p, 50p

1) For 79 paise: 50p(1) + 25p(1) + 2p(2) = 4 coins

2) For 66 paise: 50p(1) + 10p(1) + 2p(3) = 5 coins

3) For Re 1.01 (101 paise): 50p(1) + 25p(2) + 10p(2) + 2p(3) = 8 coins
Total = 4+5+8=17 coins


NIMCET PYQ
Kha-kha is an obscure island which is inhabited by two types of people : the “Yes” type and the “No” type. Native of type ‘Yes' ask only questions the right answer to which is ‘Yes' while those of type ‘No' ask only questions the right answer to which is ‘No'. For example the ‘Yes' type will ask questions like “Is 2 plus 2 equal to 4?” While the “No” type will ask questions like “Is 2 plus 2 equal to 5?”. The following question is based on your visit to the island Kha-Kha.

Kevin and Kumar are brothers from the island. Kumar asks you. Is at least one of us is of type ‘No' ? You can conclude that





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2016 PYQ

Solution

Logic Puzzle: Yes and No Types on Kha-Kha Island

Given:

  • “Yes” type always asks questions where the truthful answer is Yes.
  • “No” type always asks questions where the truthful answer is No.

Scenario:

Kumar asks: "Is at least one of us of type 'No'?"


Analyze:

Let’s consider possibilities:

  1. Assume Kumar is “Yes” type:
    • Question must have truthful answer = “Yes”.
    • So, “At least one of us is ‘No’” is true.
    • Therefore, Kevin or Kumar is “No” type.
    • Since Kumar is “Yes” type, Kevin must be “No” type.
  2. Assume Kumar is “No” type:
    • Question must have truthful answer = “No”.
    • So, “At least one of us is ‘No’” is false.
    • That means neither Kumar nor Kevin is “No” type.
    • This contradicts Kumar being “No” type.
    • So, this is impossible.

Conclusion:

Kumar is a “Yes” type, and Kevin is a “No” type.


NIMCET PYQ
You are given two (unmarked) containers of capacity 9 liters and 4 liters, and a huge tank of water. Need is to get a measure of exactly 6 liters of water. A move is either filling a container completely or emptying a container (either fully or partly). The smallest number of moves needed to do this task is





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2008 PYQ

Solution

Using 9 L and 4 L containers, the minimum sequence of fill and empty operations to obtain exactly 6 liters requires 8 moves.

NIMCET PYQ
Four friends – Arjan, Bhuvan, Guran and Lakha were comparing the number of sheep they owned. Guran has 10 more sheep than Lakha. Arjan gave one third to Bhuvan, Bhuvan gave one fourth of what he then held to Guran, Guran passed one fifth of his holding to Lakha. After this, all had equal number of sheep. How many sheep did each possess? (Minimum possible)





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2008 PYQ

Solution

Assume the final equal number and work backwards so that all transfers are integers. The minimum set satisfying all conditions is: Arjan = 90, Bhuvan = 50, Guran = 55, Lakha = 45.

NIMCET PYQ
The office staff of XYZ Corporation presently consists of three bookkeepers, P, Q, R and 5 secretaries
S, T, U, V, W. The management is planning to open a new office in another city using 2 bookkeepers
and 3 secretaries of the present staff. To do so they plan to separate certain individuals who don‟t
function well together. The following guidelines were established to set up the new office:
(i) Bookkeepers P and R are constantly finding fault with one another and should not be sent
together to the new office as a team.
(ii) R and T function well alone but not as a team, they should be separated.
(iii) S and V have not been on speaking terms and shouldn‟t go together.
(iv) Since S and U have been competing for promotion they shouldn‟t be a team. 

If $P$ is to be moved as one of the bookkeepers, which of the following cannot be a possible working unit?






Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2008 PYQ

Solution

Since $P$ is selected, $R$ cannot go. Now check secretary restrictions: $S$ and $V$ cannot go together $S$ and $U$ cannot go together

NIMCET PYQ
The office staff of XYZ Corporation presently consists of three bookkeepers, P, Q, R and 5 secretaries
S, T, U, V, W. The management is planning to open a new office in another city using 2 bookkeepers
and 3 secretaries of the present staff. To do so they plan to separate certain individuals who don‟t
function well together. The following guidelines were established to set up the new office:
(i) Bookkeepers P and R are constantly finding fault with one another and should not be sent
together to the new office as a team.
(ii) R and T function well alone but not as a team, they should be separated.
(iii) S and V have not been on speaking terms and shouldn‟t go together.
(iv) Since S and U have been competing for promotion they shouldn‟t be a team. 

If $R$ and $U$ are moved to the new office, how many combinations are possible?






Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2008 PYQ

Solution

If $R$ is selected, then $P$ and $T$ cannot go. So the second bookkeeper must be $Q$. Secretaries already include $U$. Remaining two must be chosen from $S, V, W$ such that $S$ and $U$ cannot go together → $S$ is excluded Possible pairs: $(V, W)$ only So only one valid combination exists.

NIMCET PYQ
The office staff of XYZ Corporation presently consists of three bookkeepers, P, Q, R and 5 secretaries
S, T, U, V, W. The management is planning to open a new office in another city using 2 bookkeepers
and 3 secretaries of the present staff. To do so they plan to separate certain individuals who don‟t
function well together. The following guidelines were established to set up the new office:
(i) Bookkeepers P and R are constantly finding fault with one another and should not be sent
together to the new office as a team.
(ii) R and T function well alone but not as a team, they should be separated.
(iii) S and V have not been on speaking terms and shouldn‟t go together.
(iv) Since S and U have been competing for promotion they shouldn‟t be a team. 

If $R$ is sent to the new office, which member of the staff cannot go with $R$?






Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2008 PYQ

Solution

From the conditions: $R$ cannot go with $P$ $R$ cannot go with $T$ Among the given options, only $S$ is indirectly restricted through combinations. But $S$ causes conflict when paired with $U$ or $V$, not $R$. However, selecting $S$ with $R$ may force invalid secretary combinations. Thus $S$ cannot be safely included with $R$.

NIMCET PYQ
The office staff of XYZ Corporation presently consists of three bookkeepers, P, Q, R and 5 secretaries
S, T, U, V, W. The management is planning to open a new office in another city using 2 bookkeepers
and 3 secretaries of the present staff. To do so they plan to separate certain individuals who don‟t
function well together. The following guidelines were established to set up the new office:
(i) Bookkeepers P and R are constantly finding fault with one another and should not be sent
together to the new office as a team.
(ii) R and T function well alone but not as a team, they should be separated.
(iii) S and V have not been on speaking terms and shouldn‟t go together.
(iv) Since S and U have been competing for promotion they shouldn‟t be a team. 

If $S$ goes to the new office, which of the following is true?






Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2008 PYQ

Solution

If $S$ is selected:

$V$ cannot go (condition iii)

$U$ cannot go (condition iv)

Remaining secretaries must include $T$ and $W$.
Since $T$ is selected, $R$ cannot go (condition ii).

Thus $R$ cannot go and $W$ must go.

NIMCET PYQ
Each of the five people K, L, M, P and Q is of a different weight. It is known that the number of people heavier than P is the same as the number of people lighter than Q. L is the heaviest and K is not the lightest. Who is the lightest?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2019 PYQ

Solution


NIMCET PYQ
In the middle of the confounded desert, there is the lost city of “Ash”. City is 120 miles from start. Each person can carry enough rations for 5 days and max travel per day is 30 miles. Need to reach the city, stay overnight, and return to the coast without running out of supplies. Minimum persons needed?






Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2008 PYQ

Solution

Distance one-way $=120$ miles $=4$ days.
Round trip with overnight $=4+1+4=9$ days for at least one person.
Since each carries only 5 days, support persons must relay supplies and return.
Minimum possible group that can manage relay + return safely is 4 persons.

NIMCET PYQ
Some friends planned to contribute equally to jointly buy a CD player. However, two of them decided to withdraw at the last minute. As a result, each of the others had to shell out one rupee more than what they had planned for. If the price (in Rs.) of the CD player is an integer between 1000 and 1100, find the number of friends who actually contributed?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2019 PYQ

Solution

Quick Solution:

Let number of friends planned = \( n \)

Price \( P = \) between 1000 and 1100

Equation:

\(\displaystyle \frac{P}{n-2} - \frac{P}{n} = 1 \implies P = \frac{n(n-2)}{2}\)

Try \( n = 46 \):

\( P = \frac{46 \times 44}{2} = 1012 \) (valid)

Number of friends who actually contributed = \( n - 2 = 44 \)


NIMCET PYQ
Two persons S and M have made the following statements among themselves. 
S says that I am certainly not over 40 years. 
M says that I am 38 years and you are at least 5 year old than me. 
S says you are at least 39 years. 
If all the above statements are wrong, what are the ages of M and S?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2017 PYQ

Solution


NIMCET PYQ
Each family in a locality has at most two adults, and no family has fewer than 3 children. Considering all the families together, there are more adults than boys, more boys than girls, and more girls than families. Then the minimum possible number of families in the locality is





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2019 PYQ

Solution

Let nf be number of families, ng be number of girls, nb be number of boys and nbe number of adults.
 
number of adults more than number of boys, number of boys more than number of girls and number of girls more than number of families.
 
hence we have,  na > nb > ng > nf  ..........................(1)
 
we check the above relation (1) with different values for number of families, starting with n= 1
 
Let n= 1 , then nb + n= 3  , if ng =2 then nb = 1 . But number of boys is greater than number of girls.
due to this contradiction, nf ≠ 1

Let n= 2 , then nb + n= 6  , if ng =3 then nb = 3 . But number of boys is greater than number of girls.
due to this contradiction, nf ≠ 2
 
Let n= 3 , then nb + n= 9  , if ng =4 then nb = 5 . number of adults na = 6.
 
hence the relation na > nb > ng > nf  is satisfied for the above numbers,  6>5>4>3
hence minimum number of families is 3


NIMCET PYQ
Three Gold (G) coins, three Silver (S) coins and three Copper (C) coins are arranged in a single row as follow:
G S C G S C G S C

Only 2 adjacent unlike coins can be moved at any one time.
The moved coins must be in contact with at least one other coin in line.
No coin pairs can be reversed.
What is the minimum number of moves required to get all the coins in following order?
C C C S S S G G G






Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2008 PYQ

Solution

Given restrictions allow only adjacent unlike-pair shifts without reversing order.
Step-by-step optimal shifting gives minimum 8 moves.

NIMCET PYQ
Sports (and game) persons P, Q, R, S, T, and U of a university are at the Bangalore Airport. Five of
them are selected players and leaving to participate in the Grand Sports Event in five different
events cricket, chess, carom, badminton and table tennis being held at 5 different cities Mumbai,
Chennai, Kolkata, Delhi and Hyderabad.
(a) P is going to Delhi, but he does not play either cricket or carom.
(b) Q has come to give send off to R, who is a chess player and is not leading to either Mumbai or
Hyderabad.
(c) S is leaving to Kolkata to play table tennis.
(d) U is leaving to Mumbai but he does not play either badminton or cricket.
(e) T is not a selected player. 

Who plays badminton?






Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2008 PYQ

Solution

S plays table tennis.
R plays chess.
U does not play badminton or cricket.
P does not play cricket or carom.
The only person left who can play badminton is P.

NIMCET PYQ
Sports (and game) persons P, Q, R, S, T, and U of a university are at the Bangalore Airport. Five of
them are selected players and leaving to participate in the Grand Sports Event in five different
events cricket, chess, carom, badminton and table tennis being held at 5 different cities Mumbai,
Chennai, Kolkata, Delhi and Hyderabad.
(a) P is going to Delhi, but he does not play either cricket or carom.
(b) Q has come to give send off to R, who is a chess player and is not leading to either Mumbai or
Hyderabad.
(c) S is leaving to Kolkata to play table tennis.
(d) U is leaving to Mumbai but he does not play either badminton or cricket.
(e) T is not a selected player. 

Cricketer goes to






Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2008 PYQ

Solution

P does not play cricket.
U does not play cricket.
R plays chess.
S plays table tennis.
So Q must be the cricketer.
Cities left for Q is Hyderabad.

NIMCET PYQ
Sports (and game) persons P, Q, R, S, T, and U of a university are at the Bangalore Airport. Five of
them are selected players and leaving to participate in the Grand Sports Event in five different
events cricket, chess, carom, badminton and table tennis being held at 5 different cities Mumbai,
Chennai, Kolkata, Delhi and Hyderabad.
(a) P is going to Delhi, but he does not play either cricket or carom.
(b) Q has come to give send off to R, who is a chess player and is not leading to either Mumbai or
Hyderabad.
(c) S is leaving to Kolkata to play table tennis.
(d) U is leaving to Mumbai but he does not play either badminton or cricket.
(e) T is not a selected player. 

Player of which game goes to Delhi?






Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2008 PYQ

Solution

P goes to Delhi.
P plays badminton.

NIMCET PYQ
Persons X, Y, Z and Q live in red, green, yellow or blue houses placed in a sequence on a street. Z lives in a yellow house. The green house is adjacent to the blue house. X does not live adjacent to Z. The yellow house is in between the green and red house. The color of the house X lives in is





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2010 PYQ

Solution

Yellow is between Green and Red → order must be Green – Yellow – Red. Blue must be next to Green → Blue – Green – Yellow – Red. Z lives in Yellow. X cannot be next to Z → cannot be in Green or Red. So X must be in Blue. Correct answer: Blue

NIMCET PYQ
Sports (and game) persons P, Q, R, S, T, and U of a university are at the Bangalore Airport. Five of
them are selected players and leaving to participate in the Grand Sports Event in five different
events cricket, chess, carom, badminton and table tennis being held at 5 different cities Mumbai,
Chennai, Kolkata, Delhi and Hyderabad.
(a) P is going to Delhi, but he does not play either cricket or carom.
(b) Q has come to give send off to R, who is a chess player and is not leading to either Mumbai or
Hyderabad.
(c) S is leaving to Kolkata to play table tennis.
(d) U is leaving to Mumbai but he does not play either badminton or cricket.
(e) T is not a selected player. 

Who plays chess and where is he going?






Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2008 PYQ

Solution

R is the chess player.
He is not going to Mumbai or Hyderabad.
S is going to Kolkata, P to Delhi.
So R must be going to Chennai.

NIMCET PYQ
caterpillar crawls up a pole of 75 inches high standing from the ground. Each day is crawls up 5 inches and each night it slides down 4 inches. When will it reach the top of the pole?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2017 PYQ

Solution

Caterpillar Climbing Problem

Pole height = 75 inches
Climbs up = 5 inches/day
Slides down = 4 inches/night

Net climb per day (after sliding): 5 - 4 = 1 inch

On the last day, caterpillar reaches the top without sliding back.

So, after n days, it reaches or passes 75 inches.

At the start of the nth day, it has climbed:

(n - 1) × 1 = n - 1 inches

On the nth day, it climbs 5 inches:

(n - 1) + 5 ≥ 75

Solving for n:

n - 1 + 5 ≥ 75
n + 4 ≥ 75
n ≥ 71

Answer: The caterpillar reaches the top on the 71st day.


NIMCET PYQ
Four players A, B, C, and D have to form into two pairs, however, no pair can play together more than seven times in a row A and B have played seven games in a row. C and D have three in a row. C does not to work with A. Who should play with B?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2014 PYQ

Solution


NIMCET PYQ
Given below is a binary tree, where every letter has been coded with a
string of digits 0 and 1. At any node going left is denoted by 1; at any node going right is denoted by 0. Thus
N is denoted as: 10000. All the codes are in Binary notation.
What will be the code for S?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2010 PYQ

Solution

Trace path from root to S: Right → Right → Left → Left → Left Right = 0, Left = 1 So S = 0 1 1 1 1 = 01111

NIMCET PYQ
Given below is a binary tree, where every letter has been coded with a
string of digits 0 and 1. At any node going left is denoted by 1; at any node going right is denoted by 0. Thus
N is denoted as: 10000. All the codes are in Binary notation.
Which letter is represented by 11001?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2010 PYQ

Solution

Trace 11001 = Left → Left → Right → Right → Left This path leads to letter G.

NIMCET PYQ
Given below is a binary tree, where every letter has been coded with a
string of digits 0 and 1. At any node going left is denoted by 1; at any node going right is denoted by 0. Thus
N is denoted as: 10000. All the codes are in Binary notation.
What is the value of C + R in binary notation?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2010 PYQ

Solution

Code for C = 1110 Code for R = 1001 Add (binary): 1110 +1001 = 10111 This is not in options → correct is “none of these”.

NIMCET PYQ
Given below is a binary tree, where every letter has been coded with a
string of digits 0 and 1. At any node going left is denoted by 1; at any node going right is denoted by 0. Thus
N is denoted as: 10000. All the codes are in Binary notation.
If all the codes are converted into decimal notation, then how many letters have their values greater than L?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2010 PYQ

Solution

Code for L = 0110 (decimal 6) Letters greater than L (higher numeric code): N = 0111 → 7 S = 01111 → 15 X = 000 → 0 (not greater) Others are lower. So only N and S → 2 letters.

NIMCET PYQ
Read the following information carefully and answer the questions
that follow
(1) There is group of five persons - P, Q, R, S and T.
(2) One of them is a horticulturist, one is a physicist, one is a journalist, one is an industrialist and one is
an advocate.
(3) Three of them - P, R and advocate prefer tea to coffee and two of them –Q and the journalist prefer
coffee to tea.
(4) The industrialist, S and P are friends to one another but two of these prefer coffee to tea.
(5) The horticulturist is R's brother.

Who is a horticulturist?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2010 PYQ

Solution

From (4), among industrialist, S and P, exactly two prefer coffee. From (3), P prefers tea, so the industrialist and S must be the two coffee drinkers. From (3) again, the only coffee drinkers are Q and the journalist. Hence industrialist = Q and journalist = S. The horticulturist is R’s brother, so he is different from R. Horticulturist cannot be Q (industrialist) or S (journalist), so it must be P.

NIMCET PYQ
Read the following information carefully and answer the questions
that follow
(1) There is group of five persons - P, Q, R, S and T.
(2) One of them is a horticulturist, one is a physicist, one is a journalist, one is an industrialist and one is
an advocate.
(3) Three of them - P, R and advocate prefer tea to coffee and two of them –Q and the journalist prefer
coffee to tea.
(4) The industrialist, S and P are friends to one another but two of these prefer coffee to tea.
(5) The horticulturist is R's brother.

Who is an industrialist?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2010 PYQ

Solution

As above, the two coffee drinkers are Q and the journalist. From (4) the industrialist and S are the two coffee drinkers in the trio {industrialist, S, P}, so industrialist and S must be Q and the journalist. Therefore industrialist = Q.

NIMCET PYQ
Read the following information carefully and answer the questions
that follow
(1) There is group of five persons - P, Q, R, S and T.
(2) One of them is a horticulturist, one is a physicist, one is a journalist, one is an industrialist and one is
an advocate.
(3) Three of them - P, R and advocate prefer tea to coffee and two of them –Q and the journalist prefer
coffee to tea.
(4) The industrialist, S and P are friends to one another but two of these prefer coffee to tea.
(5) The horticulturist is R's brother.

Which of the following groups include a person who likes tea but is not an advocate?





Go to Discussion

NIMCET Previous Year PYQ NIMCET NIMCET 2010 PYQ

Solution

We already have: Q = industrialist (coffee), S = journalist (coffee). Professions left for P, R, T are horticulturist, physicist, advocate. From the data, advocate must be different from P and R, so advocate = T. Thus tea drinkers are P, R and T, but the one who is an advocate is T. Persons who like tea but are not an advocate are P and R only. None of the given groups consists only of persons who like tea and are not advocates; each listed group either contains T (the advocate) or a coffee drinker. So the correct choice is “None of these”.


NIMCET


Online Test Series,
Information About Examination,
Syllabus, Notification
and More.

Click Here to
View More

NIMCET


Online Test Series,
Information About Examination,
Syllabus, Notification
and More.

Click Here to
View More

Ask Your Question or Put Your Review.

loading...