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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
A, B, C, D and E distribute some cards among themselves in a manner that A gets one less than B; C gets 5 more than D; E gets 3 more than B while D gets as many as B. Who gets the least cards?
Solution
Solution:
Let B = x.
Then D = x (D gets as many as B).
A = x − 1
C = D + 5 = x + 5
E = B + 3 = x + 3
Smallest value is x − 1 (with A).
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