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Previous Year Question (PYQs)
1
An arithmetic progression has 3 as its first term.
Also, the sum of the first 8 terms is twice the sum of
the first 5 terms. Then what is the common
difference?
Solution
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if T1=3
then (T1+T2+....+T8)=2(T1+T2+...+T5)
then n/2(2a+(n-1)d)=2(n/2(2a+(n-1)d)
T1=a=3
then we put the value of a in the equation
d=3/4
That is the answer.
Commented Jun 15 , 2021
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