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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
Three cities A, B, C are equidistant from each other.
A motorist travels from A to B at 30km/hour, from B
to C at 40km/hour, and from C to A at 50km/hour.
Then the average speed is
Solution
Let the distance between each pair of cities = d km.
Step 1: Distances & Speeds
- A → B: distance = d, speed = 30 km/h
- B → C: distance = d, speed = 40 km/h
- C → A: distance = d, speed = 50 km/h
Step 2: Total Distance
Total distance = d + d + d = 3d
Step 3: Total Time
Time = (d/30) + (d/40) + (d/50)
= d × (1/30 + 1/40 + 1/50)
LCM of (30,40,50) = 600
⇒ (20 + 15 + 12)/600 = 47/600
Total time = d × (47/600) = (47d / 600)
Step 4: Average Speed
Average speed = Total distance / Total time
= (3d) ÷ (47d/600)
= (3d × 600) / 47d
= 1800 / 47
≈ 38.3 km/h
✅ Final Answer: Average speed ≈ 38.3 km/h
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