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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
The derivative of (x3 + ex + 3x + cotx) with respect to x is
Solution
$\dfrac{d}{dx}(x^3) = 3x^2$
$\dfrac{d}{dx}(e^x) = e^x$
$\dfrac{d}{dx}(3x) = 3$
$\dfrac{d}{dx}(\cot x) = -cosec^2 x$
Therefore, total derivative $= 3x^2 + e^x + 3 - cosec^2 x$
Answer: $\boxed{3x^2 + e^x + 3 - cosec^2 x}$ ✅
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