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Previous Year Question (PYQs)



Consider the following C++ function $f()$:

unsigned int f(unsigned int n) {
unsigned int b = 0;
while (n) {
b = b + (n bitwise AND 1);
n = n shifted right by 1;
}
return b;
}

The function $f()$ returns the integer that represents the $P$ in the binary representation of positive integer $n$, where $P$ is:






Solution

The expression $n$ bitwise AND $1$ checks the last bit of $n$.

If the last bit is $1$, then $b$ increases by $1$.

After that, $n$ is shifted right by one bit.

So, the loop checks each bit of $n$ one by one.

Therefore, $b$ counts the total number of $1$'s in the binary representation of $n$.



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