In $n$-bit $2$'s complement representation, the range of signed integers is:
$-2^{n-1}$ to $2^{n-1}-1$
Here,
$n=8$
So, range is:
$-2^{7}$ to $2^{7}-1$
$=-128$ to $127$
Therefore, the minimum negative integer value is $-128$.
Online Test Series, Information About Examination,
Syllabus, Notification
and More.
Online Test Series, Information About Examination,
Syllabus, Notification
and More.