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Study Stuff for MCA Examinations - NIMCET
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Previous Year Question (PYQs)
concern a disk with a sector size of $512$ bytes, $2000$ tracks per surface, $50$ sectors per track, five double-sided platters, and average seek time of $10$ milliseconds.
If $T$ is the capacity of a track in bytes, and $S$ is the capacity of each surface in bytes, then $(T,S)=$ _____
If $T$ is the capacity of a track in bytes, and $S$ is the capacity of each surface in bytes, then $(T,S)=$ _____
Solution
Sector size $=512$ bytesNumber of sectors per track $=50$
So, capacity of one track is:
$T=512\times 50$
$T=25600$ bytes
Since,
$1K=1024$ bytes
So,
$T=\frac{25600}{1024}=25K$
Now, each surface has $2000$ tracks.
Capacity of each surface is:
$S=25K\times 2000$
$S=50000K$
Therefore,
$(T,S)=(25K,50000K)$
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