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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
Consider a machine with $16\ GB$ main memory and $32$-bits virtual address space, with page size as $4KB$. Frame size and page size is same for the given machine.
What is the minimum number of bits needed for the physical address?
What is the minimum number of bits needed for the physical address?
Solution
Main memory size $=16GB$$16GB=16\times2^{30}=2^4\times2^{30}=2^{34}$ bytes
To address $2^{34}$ bytes, number of physical address bits required is:
$34$
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