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Solution

Efficiency of the system is:

$\eta=0.578$

Given data rate is:

$1.536\ Mbps$

Maximum achievable throughput is:

$Throughput=\eta\times \text{Data rate}$

$Throughput=0.578\times1.536$

$Throughput=0.887\ Mbps$

Therefore, the maximum achievable throughput is $0.887\ Mbps$.