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Previous Year Question (PYQs)
1
Let $(2\alpha,\alpha)$ be the largest interval in which the function
$f(t)=\frac{|t+1|}{t^2},; t<0$
is strictly decreasing.
Then the local maximum value of
$g(x)=2\log(x-2)+\alpha x^2+4x-\alpha,; x>2$
is ______.
Solution
From graph ⇒ decreasing on $(-2,-1)$
$\alpha=-1$
$g(x)=2\log(x-2)-x^2+4x+1$
$g'(x)=\frac{2}{x-2}-2x+4$
$=\frac{1-(x-2)^2}{x-2}$
Critical point ⇒ $x=3$
$g(3)=2\log1-9+12+1=4$
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