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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
Let $\alpha$ and $\beta$ be the roots of equation $x^2 + 2ax + (3a + 10) = 0$ such that $\alpha < 1 < \beta$. Then the set of all possible values of $a$ is:
Solution
$\alpha < 1 < \beta$
$f(1) < 0$
$\Rightarrow 1 + 2a + (3a + 10) < 0$
$\Rightarrow 5a + 11 < 0$
$\Rightarrow a < -\frac{11}{5}$
$\therefore a \in (-\infty, -\frac{11}{5})$
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