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Previous Year Question (PYQs)
Consider a CSMA/CD network that transmits data at the rate of 100 Mbps over a 1 kilometre cable with no repeater. If the minimum frame size required for this network is 1250 bytes, what is the signal speed (km/sec) in the cable ?
Solution
Minimum frame size:
$1250 \text{ bytes} = 1250 \times 8 = 10000 \text{ bits}$
Transmission rate:
$100 \text{ Mbps} = 100 \times 10^6 \text{ bits/sec}$
Transmission time:
$T = \frac{10000}{100 \times 10^6}$
$T = 10^{-4} \text{ sec}$
In CSMA/CD:
$T = 2 \times$ propagation delay
So propagation delay:
$\frac{T}{2} = 5 \times 10^{-5}$ sec
Distance = 1 km
Signal speed:
$v = \frac{distance}{time}$
$v = \frac{1}{5 \times 10^{-5}}$
$v = 20000 \text{ km/sec}$
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