Given FDs
$CH \rightarrow C$
$A \rightarrow BC$
$B \rightarrow CEH$
$E \rightarrow A$
$A \rightarrow EFG$
From
$A \rightarrow BC$
$A \rightarrow EFG$
we get
$A \rightarrow BCFG E$
Then
$B \rightarrow CEH$
Thus
$A^+ = {A,B,C,D,E,F,G,H}$
So $A$ is a candidate key.
Now check dependency
$E \rightarrow A$
Since $E$ is not a superkey, but RHS contains a prime attribute, it satisfies 3NF but violates BCNF.
Therefore the relation is
in 3NF but not in BCNF.
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Online Test Series, Information About Examination,
Syllabus, Notification
and More.