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In a school, an auditorium was used for its cultural activities. The shape of the floor of the auditorium is rectangular with dimensions $x$ and $y$ $(x>y)$ and has fixed parameter $p$. Based on the above information answer the following questions. The area $A$ of the floor, as a function of $x$ can be expressed as:





Solution

From previous result

$p=2(x+y)$

So

$x+y=\frac{p}{2}$

Hence

$y=\frac{p}{2}-x$

Area of rectangle

$A=xy$

Substitute $y$

$A=x\left(\frac{p}{2}-x\right)$

$A=\frac{px}{2}-x^2$

$A=\frac{px-2x^2}{2}$


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