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Previous Year Question (PYQs)
4
The point of intersection of the lines
$\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}$
and
$\frac{x-4}{5}=\frac{y-1}{2}=z$
is:
Solution
First line
Let parameter $t$
$x=1+2t$
$y=2+3t$
$z=3+4t$
Second line
Let parameter $s$
$\frac{x-4}{5}=\frac{y-1}{2}=z=s$
So
$x=4+5s$
$y=1+2s$
$z=s$
For intersection
$3+4t=s$
Substitute in $x$
$1+2t=4+5(3+4t)$
$1+2t=19+20t$
$-18=18t$
$t=-1$
Then
$s=3+4(-1)=-1$
Point
$x=1+2(-1)=-1$
$y=2+3(-1)=-1$
$z=3+4(-1)=-1$
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