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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
A mixture contains milk and water in the ratio $8:x$.
If 3 litres of water is added in 33 litres of mixture, the ratio of milk and water becomes $2:1$, then value of $x$ is:
Solution
Initial ratio = $8:x$
Total mixture = 33 litres
Milk = $\frac{8}{8+x}\times 33$
Water = $\frac{x}{8+x}\times 33$
After adding 3 litres water:
Milk remains same
Water becomes
$\frac{x}{8+x}\times 33 + 3$
Given final ratio:
$\frac{\text{Milk}}{\text{Water}}=\frac{2}{1}$
So,
$\frac{\frac{8}{8+x}\times 33}{\frac{x}{8+x}\times 33 + 3}=2$
Multiply by $(8+x)$:
$\frac{264}{33x + 3(8+x)}=2$
$264=2(33x + 24 + 3x)$
$264=2(36x+24)$
$264=72x+48$
$216=72x$
$x=3$
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