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Previous Year Question (PYQs)



The mean difference between 9 paired observations is 15, and the standard deviation of differences is 5. The value of statistic $t$ is






Solution

$t=\frac{\bar{d}}{s_d/\sqrt{n}}$

$=\frac{15}{5/\sqrt{9}}=\frac{15}{5/3}=\frac{15\times3}{5}=9$



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