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Previous Year Question (PYQs)



If each of $n$ numbers $x_i = i$ is replaced by $(i+1)x_i$, then the new mean is





Solution

Original numbers: $1,2,3,\dots,n$

New values:
$(i+1)i = i^2+i$

Sum of new values:
$\sum i^2 + \sum i = \dfrac{n(n+1)(2n+1)}{6} + \dfrac{n(n+1)}{2}$

$= \dfrac{n(n+1)(2n+1+3)}{6}
= \dfrac{n(n+1)(2n+4)}{6}
= \dfrac{n(n+1)(n+2)}{3}$

New mean:
$\dfrac{(n+1)(n+2)}{3}$


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