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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
In each of the following three questions, four numbers are given. Out
of these, three are alike in a certain way but the rest one is different. Choose the one which is different
from the rest three.
Solution
Check the sum of digits:
2384 → 2+3+8+4 = 17
3629 → 3+6+2+9 = 20
3756 → 3+7+5+6 = 21
4298 → 4+2+9+8 = 23
Only 2384 gives an odd–odd pattern (two odd sums inside: 2+3=5, 8+4=12).
But the common reasoning used in such questions:
The first, third and fourth numbers are divisible by 2 in pairs (23|84, 37|56, 42|98).
But 3629 is the only one where no pair is divisible by 2.
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