The angle of intersection of the cardioids $r = a(1 + \cos\theta)$ and $r = a(1…

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The angle of intersection of the cardioids $r = a(1 + \cos\theta)$ and $r = a(1 - \cos\theta)$ is

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At intersection: a(1 + cosθ) = a(1 – cosθ) ⇒ cosθ = 0 ⇒ θ = π/2 or 3π/2 Slope formula for polar curves shows angle of intersection = 90°

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