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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
The angle between the asymptotes of the hyperbola $27x^2 - 9y^2 = 24$ is
Solution
Given hyperbola: 27x² – 9y² = 24 Divide both sides by 24: x²/(24/27) – y²/(24/9) = 1 ⇒ x²/(8/9) – y²/(8/3) = 1 Here: a² = 8/9, b² = 8/3 For hyperbola x²/a² – y²/b² = 1, angle between asymptotes = 2 tan⁻¹(b/a) Compute b/a: b/a = √( (8/3) / (8/9) ) = √3 Angle = 2 tan⁻¹(√3) = 2 × 60° = 120°Online Test Series, Information About Examination,
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