A Place for Latest Exam wise Questions, Videos, Previous Year Papers, Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
3
If $\omega \ne 1$ is a cube root of unity and $i = \sqrt{-1}$, the value of the determinant
$\left|\begin{matrix}
1 & 1+i+\omega^2 & \omega \\
1-i & -1 & \omega^2 - 1 \\
-i & -i+\omega-1 & -\omega^3
\end{matrix}\right|$
is
Solution
Solution:
Using $\omega^3 = 1$ and $\omega^2 + \omega + 1 = 0,$ simplify the entries.
After row/column reduction and applying cube root identities, the determinant becomes
$\omega^2.$
Online Test Series, Information About Examination, Syllabus, Notification and More.