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Previous Year Question (PYQs)



If area between $ y=x^{2} $ and $ y=x $ is $ A $, then area between $ y=x^{2} $ and $ y=1 $ is:





Solution

$ A = \int_{0}^{1} (x - x^{2}), dx = \frac{1}{6} $ Area between $1$ and $x^{2}$: $ \int_{0}^{1} (1 - x^{2}) dx = \frac{2}{3} = 4A $


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