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Previous Year Question (PYQs)



The number of arrangements of the letters of the word BANANA in which two N’s do not appear adjacently is …





Solution

Total letters = 6 (B, A, N, A, N, A). Total arrangements = $\dfrac{6}{32} = 60$. If two N’s are together, treat NN as one letter → letters = (NN, B, A, A, A). Arrangements = $\dfrac{5}{3} = 20$. Hence, required = $60 - 20 = 40$.


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