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Previous Year Question (PYQs)
4
If $\omega$ is a cube root of unity, then
$\left|\begin{array}{ccc}
1 & \omega & \omega^2 \\
1 & \omega^2 & 1 \\
\omega & 1 & \omega^2
\end{array}\right|$
is equal to
Solution
Use $\omega^3 = 1$ and $1 + \omega + \omega^2 = 0$.
Evaluating the determinant gives value $= -3$.
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