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Previous Year Question (PYQs)



If $a,b,c$ are in A.P., then the value of determinant $\begin{vmatrix} x+2 & x+3 & x+2a \\ x+3 & x+4 & x+2b \\ x+4 & x+5 & x+2c \end{vmatrix}$ is:





Solution

Since $a,b,c$ are in A.P. ⇒ $2b = a + c$. Expanding determinant by properties of A.P., it becomes zero.


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