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Previous Year Question (PYQs)



The equation of the circle with centre $(0, 2)$ and radius $2$ is...





Solution

Equation of circle: $(x - h)^2 + (y - k)^2 = r^2$ Substitute $(h, k) = (0, -2)$ and $r = 2$: $x^2 + (y + 2)^2 = 4 \Rightarrow x^2 + y^2 + 4y = 0.$


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