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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
If $x$, when divided by 4, leaves remainder 3,
then find the remainder when $(2020 + x)^{2022}$ is divided by 8.
Solution
Then $2020 + x = 2020 + 4k + 3 = 4k + 2023$Now $2020 \equiv 4 \pmod{8} $
$\Rightarrow 2020 + x \equiv 4 + 3 = 7 \pmod{8}$
So $(2020 + x)^{2022} \equiv 7^{2022} \pmod{8}$
Since $7 \equiv -1 \pmod{8}$,
$(-1)^{2022} = 1$.
Hence remainder = 1.
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