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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
What is the output of following C program?
void e(int x)
{
if (x > 0)
{
e(- -x);
printf("%2d", x);
e(- -x);
}
}
int main()
{
e(3);
return 0;
}
Solution
Solution:
In C, the tokens `- -x` are parsed as two unary minuses with a space, i.e. $-(-x)=x$.
So both recursive calls are `e(x)`, not `e(--x)`.
For `x=3`, the function calls itself **with the same positive value** forever:
`e(3) → e(3) → e(3) → ...` and never reaches a base case.
This causes infinite recursion (stack overflow) at run time.
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