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Previous Year Question (PYQs)
2
The 120 permutations of “MAHES” are arranged in dictionary order,
as if each were an ordinary 5-letter word.
The last letter of the $86^{th}$ word in the list is —
Solution
Total letters = 5 distinct → $5! = 120$ words.
Fixing first letter in alphabetical order: A, E, H, M, S.
Each block = $4! = 24$ words.
After A (24), E (24), H (24) → total = 72.
So the $86^{th}$ word lies in M-block (73–96).
Within M-block, order remaining letters: A, E, H, S.
Each gives $3! = 6$ words.
$73$–$78$: MA… $79$–$84$: ME… $85$–$90$: MH…
Hence, the $86^{th}$ word lies in MH-series.
So the last letter = H.
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