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Previous Year Question (PYQs)



On A={1,2,3} let R={(1,2)}. Then R is 





Solution

Not reflexive (missing $(1,1),(2,2),(3,3)$). Not symmetric (since $(2,1)\notin R$). Transitive holds vacuously because there is no pair starting at $2$ to trigger $(1,2)$∘$(2,\cdot)$.


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