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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
If there are 32 segments each of size 1K bytes, then the logical address should have
Solution
Solution: 32 segments ⇒ segment bits = $\log_2 32 = 5$. Size = 1 KB ⇒ offset bits = $\log_2 1024 = 10$.
Total address bits $= 5 + 10 = \boxed{15}$.
Answer: (D) 15 bits
Total address bits $= 5 + 10 = \boxed{15}$.
Answer: (D) 15 bits
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