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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
Number of three digit numbers that can be formed using 0, 1, 2, 3 and 5 where these digits
are allowed to repeat any number of times, is equal to
Solution
Digits available: 0, 1, 2, 3, 5 (total 5 digits).Repetition is allowed.
To form a three-digit number:
1) The first digit cannot be 0.
Possible choices = 1, 2, 3, 5 → 4 choices.
2) The second digit can be any of the 5 digits → 5 choices.
3) The third digit can also be any of the 5 digits → 5 choices.
Total three-digit numbers = $4 \times 5 \times 5 = 100$.
Final Answer: 100
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