Aspire's Library

A Place for Latest Exam wise Questions, Videos, Previous Year Papers,
Study Stuff for MCA Examinations - NIMCET

Previous Year Question (PYQs)

Consider a system with 1K pages and 512 frames and each page is of size 2 KB. How many bits are required to represent the virtual address space memory:




Solution

To determine the number of bits required to represent the virtual address space:
  • Number of pages = 1K = $2^10$.
  • Page size = 2 KB = $2^{11}$ bytes.
  • Virtual address space = Number of pages × Page size = $2^{10}×2^{11}=2^{21}$ bytes.
  • Bits required =21 bits.

Online Test Series,
Information About Examination,
Syllabus, Notification
and More.

Click Here to
View More

Online Test Series,
Information About Examination,
Syllabus, Notification
and More.

Click Here to
View More
Ask Your Question or Put Your Review.

loading...