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Study Stuff for MCA Examinations - NIMCET
Study Stuff for MCA Examinations - NIMCET
Previous Year Question (PYQs)
How much work does it take to slide a crate for a distance of 25m along a loading
dock by pulling on it with a 180 N force where the dock is at an angle of 45°
from the horizontal?
Solution
Work Done Problem:
A crate is pulled 25 m along a dock with a force of 180 N at an angle of 45°.
✅ Formula Used:
\[ \text{Work} = F \cdot d \cdot \cos(\theta) \]
✅ Substituting Values:
\[ W = 180 \times 25 \times \cos(45^\circ) = 180 \times 25 \times 0.70710678118 = 3181.98052\, \text{J} \]
✅ Final Answer (to 5 decimal places):
\[ \boxed{3.181\times 10^3 \, \text{Joules}} \]
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