Given: 30 litres mixture contains 10% water ⇒ Water = 3 litres, Milk = 27 litres
Let x litres of milk be added. Total mixture becomes (30 + x) litres. Water remains 3 litres.
We want water to be 2% of the new mixture:
Solve:
3 / (30 + x) = 2 / 100
⇒ 3 × 100 = 2 × (30 + x)
⇒ 300 = 60 + 2x
⇒ 2x = 240 ⇒ x = 120
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