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Consider the following frequency distribution table.

Class interval	10-20	20-30	30-40	40-50	50-60	60-70	70-80
Frequency	180	$f_1$	34	180	136	$f_2$	50

If the total frequency is 685 & median is 42.6 then the values of

$f_1$ and

$f_2$ are

1
2
3
4

Given: Median = 42.6, Total Frequency = 685

Using Median Formula:

$\text{Median} = L + \left( \frac{N/2 - F}{f} \right) \cdot h$

Substituting values:

$42.6 = 40 + \left( \frac{128.5 - f_1}{180} \right) \cdot 10 \Rightarrow f_1 = \boxed{82}$

Using total frequency:

$662 + f_2 = 685 \Rightarrow f_2 = \boxed{23}$

✅ Final Answer: $f_1 = 82,\quad f_2 = 23$

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