Aspire's Library
A Place for Latest Exam wise Questions, Videos, Previous Year Papers,
Study Stuff for MCA Examinations
Study Stuff for MCA Examinations
Jamia Millia Islamia Previous Year Questions (PYQs)
Jamia Millia Islamia Trigonometrical Function PYQ
Jamia Millia Islamia PYQ
Go to Discussion
Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2018 PYQ
Period of $3\sec x/3$ is
Go to Discussion
Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2018 PYQ
Solution
Period of $\sec kx$ = $\dfrac{2\pi}{k}$ → here $k = 1/3$. Hence period = $6\pi$.
Jamia Millia Islamia PYQ
Go to Discussion
Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2020 PYQ
What will be the value of
$f(x) = (\sin 3x + \sin x)\sin x + (\cos 3x - \cos x)\cos x$ ?
Go to Discussion
Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2020 PYQ
Solution
$f(x) = (\sin 3x + \sin x)\sin x + (\cos 3x - \cos x)\cos x$ $= \sin 3x \sin x + \sin^2 x + \cos 3x \cos x - \cos^2 x$ Using identity $\cos A \cos B + \sin A \sin B = \cos(A - B)$: $f(x) = \cos(3x - x) + (\sin^2 x - \cos^2 x)$ $= \cos 2x - \cos 2x = 0$
Jamia Millia Islamia PYQ
Go to Discussion
Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2019 PYQ
Period of the function $f(x) = \cos\left(\dfrac{2x}{3}\right) - \sin\left(\dfrac{4x}{5}\right)$ is:
Go to Discussion
Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2019 PYQ
Solution
Period of $\cos(\dfrac{2x}{3}) = \dfrac{2\pi}{(2/3)} = 3\pi$. Period of $\sin(\dfrac{4x}{5}) = \dfrac{2\pi}{(4/5)} = \dfrac{5\pi}{2}.$ L.C.M. of $3\pi$ and $\dfrac{5\pi}{2}$ = $15\pi$.Jamia Millia Islamia
Online Test Series,
Information About Examination,
Syllabus, Notification
and More.
View More
Jamia Millia Islamia
Online Test Series,
Information About Examination,
Syllabus, Notification
and More.
View More
Ask Your Question or Put Your Review.
