Place T, so P is two to T’s right. Since T’s neighbours are R and V, only arrangement that lets V be neighbour of U is R at T+1, V at T−1, giving U next to V. Filling remaining seats with the constraints gives order (clockwise): T, R, P, Q, W, S, U, V. Opposite to U (four away) is P.
Q, R, S, T, U and V are seated in a straight line facing North.
S is second to the right of T and T is second to the right of Q.
R is to the left of Q and second to the left of V.
What is Q’s position with respect to S?
Let positions be 1 (leftmost) to 6 (rightmost).
$T$ is second right of $Q$ ⇒ $T=Q+2$.
$S$ is second right of $T$ ⇒ $S=T+2=Q+4$.
So $Q$ can be 1 or 2.
Try $Q=2$ ⇒ $T=4$, $S=6$.
$R$ is left of $Q$ and 2 left of $V$ ⇒ take $R=1$, then $V=3$ (fits).
Arrangement: $1\!:\!R,\ 2\!:\!Q,\ 3\!:\!V,\ 4\!:\!T,\ 5\!:\!U,\ 6\!:\!S$.
Thus $Q$ is **fourth to the left** of $S$.