Jamia Millia Islamia Number Series Previous Year Question Paper and Solution with PDF

Aspire's Library

A Place for Latest Exam wise Questions, Videos, Previous Year Papers,
Study Stuff for MCA Examinations

Jamia Millia Islamia
Previous Year Questions

Jamia Millia Islamia
Previous Year Questions
Jamia Millia Islamia

Jamia Millia Islamia Previous Year Questions (PYQs)

Jamia Millia Islamia Number Series PYQ

Qus : 1 Jamia Millia Islamia PYQ

In the following series 50 is wrongly placed. Which number will come at the place of 50? 5, 16, 50, 158, 481, …

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2019 PYQ

Solution

Pattern: Multiply by 3 and add 1 → Next term = (Previous × 3) + 1 5 × 3 + 1 = 16 16 × 3 + 1 = 49 ✅ (so 50 is wrong) 49 × 3 + 1 = 148 148 × 3 + 1 = 445 (≈ 481 if pattern distorted).

Qus : 2 Jamia Millia Islamia PYQ

Next term in the following series is: 122, 197, 290, …

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2019 PYQ

Solution

Differences between terms: 197 − 122 = 75 290 − 197 = 93 Difference pattern: +18 each step Next difference = 93 + 18 = 111 Next term = 290 + 111 = 401

Qus : 3 Jamia Millia Islamia PYQ

In the series $2,,6,,18,,54,,\ldots$ what will be the $8^{\text{th}}$ term?

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2024 PYQ

Solution

Geometric progression with $a=2,\ r=3$. $n^{\text{th}}$ term $= a,r^{,n-1} = 2\cdot 3^{,n-1}$. $8^{\text{th}}$ term $= 2\cdot 3^{7} = 2\cdot 2187 = 4374$.

Qus : 4 Jamia Millia Islamia PYQ

Numbers: 517, 325, 639, 841, 792. If 2nd and 3rd digits in each number are interchanged, what will be the first digit of the second highest number?

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2018 PYQ

Solution

After swapping → 571, 352, 693, 814, 729 → arranged: 352, 571, 693, 729, 814 → 2nd highest = 729 → first digit = 7.

Qus : 5 Jamia Millia Islamia PYQ

What should come next in the following number series? $987654321,87654321,7654321$

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2018 PYQ

Solution

Each term starts from decreasing highest digit; after 7, next sequence starts with 6.

Qus : 6 Jamia Millia Islamia PYQ

Look at this series: 8, 22, 8, 28, 8, ... What number should come next?

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2020 PYQ

Solution

The pattern alternates between $8$ and increasing numbers: $22, 28, 32, ...$ (each +6). Hence, the next number after $8$ is $32$. $\boxed{\text{Answer: (C) 32}}$

Qus : 7 Jamia Millia Islamia PYQ

Which of the following is next number in the series 1, 3, 6, 11, 18, 29, … ?

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MCA 2017 PYQ

Solution

Differences: 2,3,5,7,11 → primes increasing. Next +13 → 29+13=42. $\boxed{42}$

Qus : 8 Jamia Millia Islamia PYQ

Which of the following is next number in the series 1, 8, 27, 64, 125, … ?

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MCA 2017 PYQ

Solution

Cubes: $1^3,2^3,3^3,4^3,5^3,…$ → next $6^3=216$.

Qus : 9 Jamia Millia Islamia PYQ

Which of the following is next number in the series 3, 7, 13, 21, 31, … ?

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MCA 2017 PYQ

Solution

Differences: 4,6,8,10 → next +12 → 31+12=43.

Qus : 10 Jamia Millia Islamia PYQ

Which of the following is next number in the series 1, 2, 6, 42, … ?

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MCA 2017 PYQ

Solution

Pattern: $1×1+1=2$, $2×2+2=6$, $6×7=42$, next $42×43=1806$.

Qus : 11 Jamia Millia Islamia PYQ

Which term is wrong in the series $1,\,1,\,2,\,4,\,5,\,8,\,13$ ?

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MCA 2017 PYQ

Solution

Fibonacci should be $1,1,2,3,5,8,13$. The 4th term should be $3$, not $4$.

Qus : 12 Jamia Millia Islamia PYQ

Which term is wrong in the series $2,\,5,\,8,\,12,\,14,\,17,\,20$ ?

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MCA 2017 PYQ

Solution

Should be arithmetic with $+3$: $2,5,8,11,14,17,20$. So $12$ is wrong.

Qus : 13 Jamia Millia Islamia PYQ

Find the missing number:

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2023 PYQ

Solution

Solution: Row rule: first = second × (third/2). Row1: 24 × (6/2) = 72 ✓ Row2: 16 × (12/2) = 96 ✓ Row3: 108 = ? × (18/2 = 9) ⇒ ? = 108/9 = 12.

Qus : 14 Jamia Millia Islamia PYQ

Which term is wrong in the series $1,\,4,\,9,\,16,\,21,\,36,\,49$ ?

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MCA 2017 PYQ

Solution

Perfect squares $1,4,9,16,25,36,49$. Here $21$ should be $25$.

Qus : 15 Jamia Millia Islamia PYQ

Which term is wrong in the series $1,\,3,\,6,\,11,\,15,\,21,\,28$ ?

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MCA 2017 PYQ

Solution

Triangular numbers: $1,3,6,10,15,21,28$. Here $11$ should be $10$.

Qus : 16 Jamia Millia Islamia PYQ

Find out the wrong number in the given sequence of numbers. $22,33,66,99,121,279,594$

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2018 PYQ

Solution

Pattern should alternate $\times 1.5,\ \times 2$: $22\times 1.5=33,\ 33\times 2=66,\ 66\times 1.5=99,\ 99\times 2=\mathbf{198}$ (not $121$), $198\times 1.5=\mathbf{297}$ (not $279$), $297\times 2=594$. The first error is $121$ (which also causes the later mismatch).

Qus : 17 Jamia Millia Islamia PYQ

Find out the wrong number in the given sequence of numbers. $6,13,18,25,30,37,40$

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2018 PYQ

Solution

$+7,\ +5$ repeating. $6+7=13,\ 13+5=18,\ 18+7=25,\ 25+5=30,\ 30+7=37,\ 37+5=\mathbf{42}$

Qus : 18 Jamia Millia Islamia PYQ

Insert the missing number $8, 7, 11, 12, 14, 17, 17, 22, (\ldots)$

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2018 PYQ

Solution

$= -1, +4, +1, +2, +3, 0, +5$ Pattern alternates: $(-1), (+4), (+1), (+2), (+3), (0), (+5)$ Next difference should be $+2$ (continuing + pattern after 0). $\Rightarrow 22 + 2 = 24$

Qus : 19 Jamia Millia Islamia PYQ

Insert the missing number $16, 33, 65, 131, 261, (\ldots)$

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2018 PYQ

Solution

Each term $\approx$ double of previous $+1$. $16\times2+1=33$ $33\times2-1=65$ $65\times2+1=131$ $131\times2-1=261$ $261\times2+1=523$

Qus : 20 Jamia Millia Islamia PYQ

Identify the wrong term: 31, 29, 31, 30, 28, 30, 29, 27, 26

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2022 PYQ

Solution

31→29 (−2), 29→31 (+2), 31→30 (−1), 30→28 (−2), 28→30 (+2), 30→29 (−1), 29→27 (−2), so next should be +2 → 29, not 26.

Qus : 21 Jamia Millia Islamia PYQ

Which of the following is a wrong number in the series: $78,\,57,\,36,\,19,\,10,\,2,\ ?$

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MCA 2016 PYQ

Solution

Pattern: subtract $21,\ 21,\ 17,\ 17,\ \ldots$ $78-21=57$, $57-21=36$, $36-17=19$, **$19-17=2$** (so 10 should not appear). Hence 10 is the wrong term.

Qus : 22 Jamia Millia Islamia PYQ

What will be the next number in the series? $2,\ 6,\ \_,\ 42,\ 1806,\ \_$

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MCA 2016 PYQ

Solution

Rule: multiply each term by “itself + 1” $2\to 2(2+1)=6$; $6\to 6(6+1)=42$; $42\to 42(42+1)=1806$. Next: $1806\to 1806(1806+1)=1806\times1807=3{,}263{,}442$.

Qus : 23 Jamia Millia Islamia PYQ

One term in the number series is wrong. Find the wrong term. $1,\ 2,\ 6,\ 15,\ 30,\ 56$

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MCA 2016 PYQ

Solution

Intended pattern: add consecutive squares $1+1^2=2,\ 2+2^2=6,\ 6+3^2=15,\ 15+4^2=31,\ 31+5^2=56$. So the fourth term should be $31$; hence the **wrong** shown term is $56$ vs expected $55$ at the end, or equivalently the displayed list’s mismatch flags **56** as inconsistent.

Qus : 24 Jamia Millia Islamia PYQ

Find the missing terms in the series: 2, 15, 4, 12, 6, 7, ?, ?

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2021 PYQ

Solution

Odd positions increase by +2: 2,4,6,8,…; even positions decrease by −3,−5,−7,…: 15,12,7,0.

Missing terms = 8 and 0.

Qus : 25 Jamia Millia Islamia PYQ

Find the wrong number in the series: 5, 18, 34, 54, 79, 110, 158

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2021 PYQ

Solution

solution: Differences: 13, 16, 20, 25, 31, 48. The increments should grow by +3, +4, +5, +6, +7 ⇒ last diff should be 38, not 48. Expected last term = 110 + 38 = 148.

Qus : 26 Jamia Millia Islamia PYQ

Find the wrong number in the series: 5, 6, 14, 45, 184, 920, 5556

1
2
3
4
Go to Discussion

Jamia Millia Islamia Previous Year PYQ Jamia Millia Islamia JAMIA MILLIA ISLAMIA MCA 2021 PYQ

Solution

multiply by n and add n: ×1+1, ×2+2, ×3+3, ×4+4, ×5+5, ×6+6 …

After 184, next should be 184×5+5 = 925, not 920. Then 925×6+6 = 5556 fits.

Jamia Millia Islamia

Online Test Series,
Information About Examination,
Syllabus, Notification
and More.

Click Here to
View More

Jamia Millia Islamia

Online Test Series,
Information About Examination,
Syllabus, Notification
and More.

Click Here to
View More

Ask Your Question or Put Your Review.

Please provide more information - at least 10 characters

Feedback

Info.

Information

Aspire's Library

Jamia Millia Islamia Previous Year Questions (PYQs)

Jamia Millia Islamia Number Series PYQ

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Solution

Jamia Millia Islamia

Jamia Millia Islamia

Info.

Confirm Delete

Edit