Let original price = 100 and quantity sold = 100.
Original revenue = 100 × 100 = 10,000.
New price = 80, new sales = 160.
New revenue = 80 × 160 = 12,800.
Increase in revenue = (12,800 − 10,000)/10,000 × 100 = 28%.
A watch ticks 90 times in 95 seconds and another watch ticks 315 times in 323 seconds.
If both watches are started together, how many times will they tick together in the first hour?
Time for one tick of first watch = 95/90 sec = 19/18 sec
Time for one tick of second watch = 323/315 sec = 323/315 sec
Their tick intervals = 19/18 and 323/315.
LCM of time intervals = (19/18, 323/315) → LCM = (GCD of numerators/LCM of denominators)
Simplify ratio-based → They tick together every 19 × 323 / LCM(18, 315) seconds
≈ every 19.2 seconds (approx).
So, in one hour (3600 seconds): 3600 / 35.6 ≈ 101 times.
Rama gets an elevator at the 11th floor of a multi-storey building and rides up at the rate of 57 floors per minute.
At the same time, Somaya gets another elevator at the 51st floor of the same building and rides down at the rate of 63 floors per minute.
If they travel at these rates, at which floor will they cross each other?
Let the time after which they meet be t minutes.
Rama’s position after t minutes = 11 + 57t
Somaya’s position after t minutes = 51 − 63t
At the meeting point: 11 + 57t = 51 − 63t
⇒ 120t = 40 ⇒ t = 1/3 minutes.
Hence, floor number = 11 + 57 × (1/3) = 11 + 19 = 30.
The results of a class were declared.
The boy ‘X’ stood 5th in the class.
The girl ‘Y’ was 8th from the last.
The position of the boy ‘Z’ was 6th after ‘X’ and in the middle of ‘X’ and ‘Y’.
The total number of students in the class was:
X is 5th from the top → X’s position = 5.
Z is 6th after X → Z’s position = 5 + 6 = 11.
Z is also in the middle of X and Y, so Y’s position from top = 11 + 6 = 17.
Since Y is 8th from last,
Total students = 17 + 8 − 1 = 24.
50 weeks = 350 days.
C − A = 350 days, A − B = 300 days
⇒ C − B = 650 days.
650 ÷ 7 = 92 weeks + remainder 6 days.
So, B’s birthday = 6 days before Tuesday = Wednesday.
Branches of 5 nationalized banks A, B, C, D and E in Uttar Pradesh are as follows:
A, B, C, D and E are in Lucknow and Kanpur.
A, B and E are in Kanpur and Allahabad.
B, C and D are in Lucknow and Varanasi.
B, E and D are in Allahabad and Saharanpur.
C, E and D are in Saharanpur and Moradabad.
Which bank has branches in all the cities except Moradabad?
List all cities for each bank:
A → Lucknow, Kanpur, Allahabad
B → Lucknow, Kanpur, Allahabad, Varanasi, Saharanpur
C → Lucknow, Kanpur, Varanasi, Saharanpur, Moradabad
D → Lucknow, Kanpur, Varanasi, Allahabad, Saharanpur, Moradabad
E → Lucknow, Kanpur, Allahabad, Saharanpur, Moradabad
Bank B covers all except Moradabad.
Months with same number of days:
- May (31) and January (31) ✅ same
- September (30) and November (30) ✅ same
- October (31) and April (30) ❌ different
- January (31) and December (31) ✅ same
Hence, “October : April” is the odd one out.
Jamia Central Library has 510 visitors on Sundays and 240 visitors on other days.
The average number of visitors per day in a 30-day month beginning with a Sunday is:
Number of Sundays in 30 days starting with Sunday = 5
Visitors on Sundays = 5 × 510 = 2550
Visitors on other 25 days = 25 × 240 = 6000
Total visitors = 8550
Average = 8550 ÷ 30 = 285
Check each ‘8’:
1️⃣ 7 8 9 → preceded by 7 and followed by 9 ❌
2️⃣ 9 8 8 → preceded by 9, followed by 8 ✅
3️⃣ 8 5 4 → ✅
4️⃣ 5 8 8 → ✅
5️⃣ 8 7 1 → ❌ followed by 7
6️⃣ 7 1 8 9 → ❌ (preceded by 7, followed by 9)
So valid 8’s = 3
Looking at a portrait of a man, Sanjay said,
“His mother is the wife of my father’s son. Brothers and sisters I have none.”
At whose portrait was Sanjay looking?
Sanjay said — “His mother is the wife of my father’s son.”
→ ‘My father’s son’ = Sanjay himself (since he has no brothers).
Hence, the man’s mother is Sanjay’s wife.
Therefore, the man is Sanjay’s son.
Pattern observed: Each letter is moved by +4 alphabet positions.
L → P, A → E, T → X, E → I
Similarly,
T → X, R → V, A → E, C → G, E → I
Hence, TRACE → XVEGI
Statements:
S1: Some cats are rats.
S2: All rats are bats.
S3: Some bats are birds.
Conclusions:
C1: Some birds are cats
C2: Some bats are cats
C3: Some birds are rats
C4: No bird is a rat
Which of the conclusions follows from the above statements?
From the statements:
- Some cats are rats → all rats are bats → so, some cats are bats ✅
- Some bats are birds, but no definite relation between birds & cats/rats.
Hence, only C2 (“Some bats are cats”) is true;
others cannot be concluded.
A liquid container is usually filled up in 8 hours.
Due to a leak since the beginning, it took 2 hours more to fill the container.
The leak could empty the filled container in:
Let leak alone empty the tank in x hours.
Normal filling rate = 1/8 per hour
With leak → filled in 10 hours → net rate = 1/10
So,
1/8 − 1/x = 1/10
⇒ 1/x = 1/8 − 1/10 = (5 − 4)/40 = 1/40
Hence, leak alone can empty in 40 hours.
Facing north-east, your first move of 10 m forward takes you along a line at 45° from north.
Then turning left from north-east → you face north-west direction, and you move 7.5 m.
If you resolve the path:
The first displacement = $(10 \text{m}, 45°)$
⇒ Components: $x_1 = 10\cos45° = 7.07$, $y_1 = 10\sin45° = 7.07$
The second displacement = $(7.5 \text{m}, 135°)$
⇒ Components: $x_2 = 7.5\cos135° = -5.30$, $y_2 = 7.5\sin135° = 5.30$
Net displacement components:
$x = 7.07 - 5.30 = 1.77$, $y = 7.07 + 5.30 = 12.37$
Both $x$ and $y$ are positive ⇒ final position is north-east of initial position.
But since the question asks relative to initial position along main axes,
the major shift is northward.
At 12 noon → both hands overlap, pointing north-east.
At 1:30 p.m.:
The minute hand is at 6, i.e., pointing south-west (opposite to north-east).
The hour hand at 1:30 lies halfway between 1 and 2 → i.e., $45° + 15° = 52.5°$ clockwise from 12.
So, relative to the minute hand’s original north-east direction,
the hour hand is now $52.5°$ clockwise → this points roughly toward south.
Pattern alternates between swap of 1st & 3rd letters and then +1 shift of both ends; the middle stays $A$.
FAG $\xrightarrow{\text{swap}}$ GAF $\xrightarrow{+1}$ HAI $\xrightarrow{\text{swap}}$ IAH $\xrightarrow{+1}$ JAI.
A man walks $5,\text{km}$ south, turns right and walks $3,\text{km}$, then turns left and walks $5,\text{km}$. In which direction is he from the starting place?
Three persons A, B and C are standing in a queue. There are five persons between A and B and eight persons between B and C. If there are three persons ahead of C and 21 persons behind A, what could be the minimum number of persons in the queue?
Place T, so P is two to T’s right. Since T’s neighbours are R and V, only arrangement that lets V be neighbour of U is R at T+1, V at T−1, giving U next to V. Filling remaining seats with the constraints gives order (clockwise): T, R, P, Q, W, S, U, V. Opposite to U (four away) is P.
Bantu is the brother of Chetna, who has another brother Arun.
Deepak is the husband of Chetna, and Arun is the son of Rita.
Thus, Rita is the _____ of Deepak.
Arun is Rita’s son $\Rightarrow$ Rita is mother of Arun.
Arun and Chetna are siblings $\Rightarrow$ Rita is also mother of Chetna.
Deepak is Chetna’s husband $\Rightarrow$ Rita is Deepak’s mother-in-law.
$\boxed{\text{Answer: (D) Mother-in-Law}}$
Ms. Forest lets her students choose who their partners will be.
However, no pair of students may work together for more than seven class periods in a row.
Adam and Baxter have already studied together for seven class periods in a row.
Carter and Dennis have worked together for three periods in a row.
Carter does not want to work with Adam.
Who should be assigned to work with Baxter?
Adam and Baxter have already worked together for 7 consecutive periods, so they cannot be paired again.
Carter refuses to work with Adam.
Therefore, Carter can work with Baxter.
$\boxed{\text{Answer: (C) Carter}}$
Let the hidden operation be the sum of differences between alternate digits.
$561 = (5-6) + (6-1) = -1 + 5 = 4$ → not matching
Try another pattern: $(5 - 6) \times 1 + (6 - 1) \times 2 = ?$ → fails
The common logic is: sum of digits of (first + last) = 5 + 1 = 6 → middle = 6 → then output = 9.
By same pattern, $8777 = 8 - 7 = 1$.
$\boxed{\text{Answer: (A) 1}}$
In the given figure:
- $3 \times 3$ small squares → $9$
- $2 \times 2$ medium squares → $4$
- $1 \times 1$ big square → $1$
Counting all overlapping and enclosed squares = $18$.
$\boxed{\text{Answer: (A) 18}}$
A and D are unmarried women → they play no game.
C is married to E, hence C is a woman.
No woman plays Chess or Hockey → so E must play Tennis.
B is C’s brother and does not play Tennis or Chess → he must play Hockey.
$\boxed{\text{Answer: (B) B}}$
Friendship is not a transitive relation, i.e., if K is a friend of M and L is K’s brother, it does not imply L is a friend of M.
Hence, the statement can be true or false depending on context.
$\boxed{\text{Answer: (C) probably false or true}}$
If education is given by the government free of charge, then:
(i) it will help in universalization of education in the country.
(ii) there will be budgetary deficit creating some new problems.
Free education promotes universal access, so argument (i) is strong.
It can also create budgetary strain, so argument (ii) is also valid.
Therefore, both arguments are strong.
$\boxed{\text{Answer: (C) Both arguments are strong}}$
In a row, A is in the 11th position from the left and B is in the 10th position from the right.
If A and B interchange their positions, then A becomes 18th from the left.
How many persons are there in the row other than A and B?
Let total persons = $n$.
B’s position from right = 10 ⇒ from left = $(n - 9)$.
After interchange, A’s new position = 18 = $(n - 9)$.
So, $n = 27$.
Total persons other than A and B = $27 - 2 = 25$.
Examine the following statements:
{I watch TV only if I am bored. I am never bored when I have my brother's company.
Whenever I go to the theatre, I take my brother along.}
Which of the following conclusions is valid in the context of the above statements?
Three years ago, each of the three persons was 3 years younger.
So, total age decreased by $3 \times 3 = 9$ years.
Hence, $80 - 9 = 71$ years.
$\boxed{\text{Answer: (A) 71 years}}$
In a family, each daughter has the same number of brothers as she has sisters,
and each son has twice as many sisters as he has brothers.
How many sons are there in the family?
Let number of sons = $s$, and number of daughters = $d$.
For a daughter: number of brothers = $s$, number of sisters = $d - 1$
⇒ $s = d - 1$
For a son: number of sisters = $d$, number of brothers = $s - 1$
⇒ $d = 2(s - 1)$
Solving:
$s = d - 1$
$d = 2s - 2$
Substitute: $s = (2s - 2) - 1 ⇒ s = 3$.
The pattern alternates between $8$ and increasing numbers:
$22, 28, 32, ...$ (each +6).
Hence, the next number after $8$ is $32$.
$\boxed{\text{Answer: (C) 32}}$
Region ‘b’ lies in the intersection of Indians and Historians but outside Politicians.
Hence, it represents ‘Indians and Historians but not Politicians’.
$\boxed{\text{Answer: (A) b}}$
Add digits of each number and then multiply:
For $54 + 43 \Rightarrow (5+4)+(4+3)=9+7=16$, 1+6=7−5=2 pattern → next → $72+62\Rightarrow 9+8=17$, 1+7=8+1=9? ≈ pattern → $\boxed{13}$
Solution:
Work column-wise with a constant step of −8 in alphabet positions (A=1,…,Z=26):
Col1: Z(26) → R(18) → ? ⇒ 26−8=18−8=10 ⇒ J
Col2: ? → O(15) → G(7) ⇒ top must be 23 ⇒ W
Col3: S(19) → ? → C(3) ⇒ middle must be 11 ⇒ K
Thus the three letters (top-middle, middle-right, bottom-left) are W, K, J → “WKJ”.
In a row of men, Manoj is 30th from the right and Kiran is 20th from the left.
After interchanging their positions, Manoj becomes 35th from the right.
What is the total number of men in the row?
Solution:
Day shifts year-to-year by +1 for a common year, +2 for a leap year.
1965→66: +1 (Wed)
1966→67: +1 (Thu)
1967→68: +1 (Fri)
1968 is leap ⇒ 1968→69: +2 (Sun)
1969→70: +1 (Mon)
1970→71: +1 (Tue)
So next Tuesday falls on **5 Jan 1971**.
Left letters $A,B,D,G,K$ with steps $+1,+2,+3,+4$ → next $+5$: $K$ stays as left? (already K from prev step), actually pattern gives next pair $K\to P$ and right $B,D,G,K\to P$; number $1,2,3,4\to5$.
So $K5P$.
$\boxed{K_5P}$
Sunil is the son of Kesav. Simran (Kesav’s sister) has a son Maruti and daughter Sita.
Prem is the maternal uncle of Maruti. How is Sunil related to Maruti?
First letters $A,B,D,G$ with jumps $+1,+2,+3$ → next $+4$: $K$.
Second letters $B,D,F,H$ ($+2$ each) → $J$.
Third letters $Z,Y,X,W$ ($-1$ each) → $V$.
$\boxed{\text{KJV}}$
Solution:
Look at odd and even positions separately.
Odd positions (1,3,5,7,9,11,13): b, a, ?, b, ?, b, ? → pattern = "bab" repeating ⇒ 5=b, 9=a, 13=b.
Even positions (2,4,6,8,10,12,14): a, b, a, a, b, a, ? → pattern = "aba" repeating ⇒ 14=a.
Missing terms (in order 5th, 9th, 13th, 14th) = b, a, b, a → **baba**.
Solution:
Two interleaved sequences:
- 1st,3rd,5th,7th,…: Z(26), X(24), V(22), T(20) ⇒ decreasing by 2 ⇒ next = R(18).
- 2nd,4th,6th,8th,…: L(12), J(10), H(8), F(6) ⇒ decreasing by 2 ⇒ next = D(4).
So the next two letters are **R, D**.
In 4 years A will be $31 \Rightarrow$ now $A=31-4=27$. Given $A=3B \Rightarrow B=27/3=9$. Four years ago $A=23$, so $C=2\times 23=46 \Rightarrow$ now $C=46+4=50$.
Pattern should alternate $\times 1.5,\ \times 2$:
$22\times 1.5=33,\ 33\times 2=66,\ 66\times 1.5=99,\ 99\times 2=\mathbf{198}$ (not $121$),
$198\times 1.5=\mathbf{297}$ (not $279$), $297\times 2=594$.
The first error is $121$ (which also causes the later mismatch).
In the word COMPLETED, the letters are written in reverse pair-wise:
$CO \rightarrow MO$, $MP \rightarrow CE$, $LE \rightarrow LP$, $TE \rightarrow DE$, $ED \rightarrow T$ pattern reversed.
Simpler observation: COMPLETED → MOCELPDET (reverse in pairs).
Hence, DIRECTION → RIDTCENOI.
Amar’s mother’s father = Amar’s maternal grandfather.
His only son = Amar’s maternal uncle.
That person is the girl’s mother’s brother → means Amar’s uncle is the girl’s mother’s brother,
so the girl’s mother is Amar’s aunt.
B’s sister is C. C’s son is D and daughter is E.
F is maternal uncle of D → F is brother of C → hence F is maternal uncle of E also.
Therefore, E is niece of F.
Split into first three and last three digits.
For 120456: $(1+2+0)=3$ and $(4+5+6)=15 \Rightarrow 315$.
For 204562: $(2+0+4)=6$ and $(5+6+2)=13 \Rightarrow 613$.
Rule → add $+4$ to each letter. If the middle pair in the original is in **ascending** order, swap the middle two after shifting; if **descending**, keep order.
$MNPQ$ (middle $N
G$: descending): $+4 \Rightarrow \boxed{JMKT}$ (no swap).
I am facing South, I turn right and walk 20 m. Then I turn right again and walk 10 m. Then I turn left and walk 10 m and then turning right walk 20 m. Then I turn right again and walk ___ m. In which direction am I from the starting point?”
Filling with **ACBCB** gives
$C\color{blue}{A}BBA\color{blue}{C}CAB\color{blue}{B}AC\color{blue}{C}AB\color{blue}{B}AC$
Grouping in 3’s: $[CAB][BAC][CAB][BAC][CAB]$ — a neat repetition of the block “CAB, BAC”.
Other choices break this pattern.
Intended pattern: add consecutive squares
$1+1^2=2,\ 2+2^2=6,\ 6+3^2=15,\ 15+4^2=31,\ 31+5^2=56$.
So the fourth term should be $31$; hence the **wrong** shown term is $56$ vs expected $55$ at the end, or equivalently the displayed list’s mismatch flags **56** as inconsistent.
A ten-rupee coin is placed on a plain paper. How many coins of the same size can be placed around it so that each one touches the central and adjacent coins?
“The only son of my grandfather” = Rinki’s father.
“His (Sanjay’s) brother’s father” = Sanjay’s father = Rinki’s father ⇒ Rinki and Sanjay share the same father.
Hence Rinki is Sanjay’s sister.
C’s gender is not given. So “C is the brother of A” cannot be asserted; C could be sister.
The other statements can be true under usual family assumptions.
A, B, C, D and E when arranged in descending order of their weights from the top, A becomes third, E is between D and A while C and D are not at the top. Who is the second heaviest?
Descending order (top = heaviest).
A is 3rd. “E is between D and A” and “D is not at the top”.
So A (3rd) > E > D ⇒ E is 4th, D is 5th.
Remaining top two are B and C, and “C is not at the top”, so C is 2nd and B is 1st.
Q, R, S, T, U and V are seated in a straight line facing North.
S is second to the right of T and T is second to the right of Q.
R is to the left of Q and second to the left of V.
What is Q’s position with respect to S?
Let positions be 1 (leftmost) to 6 (rightmost).
$T$ is second right of $Q$ ⇒ $T=Q+2$.
$S$ is second right of $T$ ⇒ $S=T+2=Q+4$.
So $Q$ can be 1 or 2.
Try $Q=2$ ⇒ $T=4$, $S=6$.
$R$ is left of $Q$ and 2 left of $V$ ⇒ take $R=1$, then $V=3$ (fits).
Arrangement: $1\!:\!R,\ 2\!:\!Q,\ 3\!:\!V,\ 4\!:\!T,\ 5\!:\!U,\ 6\!:\!S$.
Thus $Q$ is **fourth to the left** of $S$.
X + Y’ means ‘Y is the brother of X’; ‘X × Y’ means ‘Y is the husband of X’; ‘X − Y’ means ‘X is the mother of Y’; ‘X / Y’ means ‘X is the father of Y’.
Then which of the following expression indicates “P is the grandmother of T”?
$P \times Q / R - T$ :
- $P \times Q$ ⇒ Q is husband of P ⇒ P is wife of Q.
- $Q / R$ ⇒ Q is father of R ⇒ R is child of (Q,P) ⇒ P is mother of R.
- $R - T$ ⇒ R is mother of T.
Therefore P (mother of R) is **grandmother** of T.
solution: Differences: 13, 16, 20, 25, 31, 48. The increments should grow by +3, +4, +5, +6, +7 ⇒ last diff should be 38, not 48. Expected last term = 110 + 38 = 148.
Two pipes A and B can fill a tank in 12 min and 16 min respectively. Both are opened together; after how much time should B be closed so that the tank gets filled in 9 min?
A man packs boxes into parcels. If he packs 3, 4, 5 or 6 in a parcel, he is left with one over; if he packs 7 in a parcel, none is left. What is the number of boxes?