When you simplify algebraically the given expression to a minimum sum of products,
how many terms do you get?
(A + B' + C + E') (A + B' + D' + E) (B' + C' + D' + E')
Solution:
Let’s analyze:
We can simplify using Boolean algebra rules.
After simplification (by K-map or expansion reduction), the minimum sum of products results in **4 terms**.
Solution:
Simplify step-by-step:
$A'CD'E + A'B'D' + ABCE + ABD$
→ Combine using absorption and distributive laws.
$A'B'D' + ABD + ACD'E$
Hence, the final simplified expression is:
$(p \land q) \to (p \lor q)$
This statement is always true, since whenever both $p$ and $q$ are true, $p \lor q$ is also true.
Hence, it represents a **Tautology**, not negation.