Given:
$a^4 = e$
$b^2 = e$
Also $a^3 b = ba$
Multiply by $a$:
$a^4 b = baa$
$b = baa$
$ab = a(baa) = (ab)^{-1}$
Hence $(ab)^2 = e$
Therefore order of $ab = 2$
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